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TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
ok Hemant answered 4 years ago Standard Formula : ∫ [ 1 / √( a²  u² ) ] du = arcsin ( u / a ) ........... (1) ......................................... I = ∫ [ 1 / √( x  x² ) ] dx ............. (2) ......................................... We have √( x  x² ) = √[  ( x²  x ) ] = √[ (1/4)  ( x²  x + 1/4 ) ] = √[ (1/2)²  ( x 1/2 )² ] ..... (3) ......................................... From (2) and (3), then, I = ∫ { 1 / √[ (1/2)²  ( x 1/2 )² ] } dx ..= ∫ { 1 / √[ (1/2)²  u² ] } du, ............ where ... u = x  1/2 ..= arcsin [ u / (1/2) ] + C................... from (1) ..= arcsin [ 2u ] + C ..= arcsin [ 2( x  1/2 ) ] + C ..= arcsin ( 2x  1 ) + C
 10 months ago

TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
do this help!!
 10 months ago

TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
omg do this help???????????????!!!!!!!!!
 10 months ago
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