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TheRealMeeeeeBest ResponseYou've already chosen the best response.1
ok Hemant answered 4 years ago Standard Formula : ∫ [ 1 / √( a²  u² ) ] du = arcsin ( u / a ) ........... (1) ......................................... I = ∫ [ 1 / √( x  x² ) ] dx ............. (2) ......................................... We have √( x  x² ) = √[  ( x²  x ) ] = √[ (1/4)  ( x²  x + 1/4 ) ] = √[ (1/2)²  ( x 1/2 )² ] ..... (3) ......................................... From (2) and (3), then, I = ∫ { 1 / √[ (1/2)²  ( x 1/2 )² ] } dx ..= ∫ { 1 / √[ (1/2)²  u² ] } du, ............ where ... u = x  1/2 ..= arcsin [ u / (1/2) ] + C................... from (1) ..= arcsin [ 2u ] + C ..= arcsin [ 2( x  1/2 ) ] + C ..= arcsin ( 2x  1 ) + C
 4 months ago

TheRealMeeeeeBest ResponseYou've already chosen the best response.1
omg do this help???????????????!!!!!!!!!
 4 months ago
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