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TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
ok Hemant answered 4 years ago Standard Formula : ∫ [ 1 / √( a²  u² ) ] du = arcsin ( u / a ) ........... (1) ......................................... I = ∫ [ 1 / √( x  x² ) ] dx ............. (2) ......................................... We have √( x  x² ) = √[  ( x²  x ) ] = √[ (1/4)  ( x²  x + 1/4 ) ] = √[ (1/2)²  ( x 1/2 )² ] ..... (3) ......................................... From (2) and (3), then, I = ∫ { 1 / √[ (1/2)²  ( x 1/2 )² ] } dx ..= ∫ { 1 / √[ (1/2)²  u² ] } du, ............ where ... u = x  1/2 ..= arcsin [ u / (1/2) ] + C................... from (1) ..= arcsin [ 2u ] + C ..= arcsin [ 2( x  1/2 ) ] + C ..= arcsin ( 2x  1 ) + C
 one year ago

TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
do this help!!
 one year ago

TheRealMeeeee Group TitleBest ResponseYou've already chosen the best response.1
omg do this help???????????????!!!!!!!!!
 one year ago
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