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So you want the slopes of the intersecting line segments to be perpendicular, agreed?

Yeah

They are the opposite recipricols and I knew what you meant haha

and i guess they were talking about the midpoints

not where the line segments intersect

|dw:1386186685552:dw|
pretend that is perfect

they already give you the midpoints

just show the slopes are undefined and 0 with those points given

like look at one line segment at a time
Take the line segment with (-a,b) and (-a,-b)

find the slope

then do the same with the line segment going through (-a,b) and (a,b)

how do you find the slope of that though?

all the points on x=a have what in common?

look at the line segment going through the midpoints

you were trying to show that one thing is a rectangle

oops I meant to say how do I prove its a rectangle

we did that by showing the angles were 90 degrees.

We show that by showing the line segments were perpendicular.

we knew the line segments were perpendicular because one was horizontal and the other was vertical

Okay so there arent any formulas that I have to include or anything?

If you want you could use that one formula I mentioned

The slope formula right? but I don't really need it

Okay. that makes sense. Thanks for your help!

np