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solve the equation. Give a general formula for all the solutions. 2 cosθ + 1 = 0
 4 months ago
 4 months ago
solve the equation. Give a general formula for all the solutions. 2 cosθ + 1 = 0
 4 months ago
 4 months ago

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SalmonBest ResponseYou've already chosen the best response.1
\[2\cos \theta+1=0\] \[2\cos \theta= 1\] \[\cos \theta=\frac{ 1 }{ 2 }\] \[\cos \theta=\cos \frac{ \pi }{ 3 }\] \[\cos \theta=\cos(\pi+\frac{ \pi }{ 3 })\] \[\theta=2n \pi \pm \frac{ \pi }{ 3 }\] ...where \[n \epsilon I\]
 4 months ago

myphuong32491Best ResponseYou've already chosen the best response.0
The answer choice are A.) θ=3π/2+kπ B.) θ=2π/3+2kπ, θ=4π/3+2kπ C.) θ=π/2+2kπ, θ=3π/2+2kπ D.) θ=2π/3+kπ, θ=4π/3+kπ
 4 months ago

SalmonBest ResponseYou've already chosen the best response.1
hey sry I was wrong in last step \[\theta=2n \pi+\frac{ 4\pi }{ 3 }\]..........(1) and \[\theta=2n \pi\frac{ 4\pi }{ 3 }\] ........(2) where nϵI now put n=k in equation 1 and n= k+1 in equation 2 you will get the answer
 4 months ago

myphuong32491Best ResponseYou've already chosen the best response.0
That's fine. Thank you so much ^^
 4 months ago
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