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so far i have
Yep that's right
then i multiplied and simplified basically there's alot more to right out but i cant seem to solve for A or B
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If you have C and D you can sub in two arbitrary x values that aren't -4 or 4 and you can build a system of equations
but wouldn't that leave you with two things to solve for or am i misunderstanding you
A and B should be easiest to solve for unless I messed up somewhere
sub x = 4, you find C. sub x = -4, you find D. Next you can sub x = 1 and x = 2, that gives you two equations with two unknowns you can solve.
So you are suppose to have
\[1=x^3(0)+x^2(0)+x(0)+1\] (so we can have 1=1)
and you have
You have 4 equations to solve.
These easiest two equations to solve are the last two since there is only one unknown in each.