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I need some help on this practice problem for Python.Positive root of the following equation:
34*x^2 + 68*x  510
Recall:
a*x^2 + b*x + c
x1 = (  b + sqrt ( b*b  4*a*c ) ) / ( 2*a )
what I typed is...
>>> import math
>>> math.sqrt(68*684*34*510)
272.0
>>> (68+sqrt(68*684*34*510))/(2*34)
but I keep getting
Traceback (most recent call last):
File "<pyshell#2>", line 1, in <module>
(68+sqrt(68*684*34*510))/(2*34)
NameError: name 'sqrt' is not defined
Can anyone help me with this and explain it?
Thanks a lot. I am a beginner...
 4 months ago
 4 months ago
I need some help on this practice problem for Python.Positive root of the following equation: 34*x^2 + 68*x  510 Recall: a*x^2 + b*x + c x1 = (  b + sqrt ( b*b  4*a*c ) ) / ( 2*a ) what I typed is... >>> import math >>> math.sqrt(68*684*34*510) 272.0 >>> (68+sqrt(68*684*34*510))/(2*34) but I keep getting Traceback (most recent call last): File "<pyshell#2>", line 1, in <module> (68+sqrt(68*684*34*510))/(2*34) NameError: name 'sqrt' is not defined Can anyone help me with this and explain it? Thanks a lot. I am a beginner...
 4 months ago
 4 months ago

This Question is Closed

salbBest ResponseYou've already chosen the best response.1
what were you expecting when you wrote "(68+sqrt(68*684*34*510))/(2*34)" ?
 4 months ago

salbBest ResponseYou've already chosen the best response.1
You either need to do: "from math import* if you don't want to type math.sqrt(2) and just say sqrt(2) or "from math import as m" so you could use m.sqrt(2). All I know is that how importing and using libraries works in python.
 4 months ago

knowledgegainerBest ResponseYou've already chosen the best response.0
Hi thank you for your reply. When I wrote "(68+sqrt(68*684*34*510))/(2*34)" , I was expecting to get the final result.But I didn't get the final result, I got NameError: name 'sqrt' is not defined instead.
 4 months ago

salbBest ResponseYou've already chosen the best response.1
"(68+math.sqrt(68*684*34*510))/(2*34)" is what you would want then in your case
 4 months ago

knowledgegainerBest ResponseYou've already chosen the best response.0
Thank you so much, salb
 4 months ago
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