I need some help on this practice problem for Python.Positive root of the following equation: 34*x^2 + 68*x - 510 Recall: a*x^2 + b*x + c x1 = ( - b + sqrt ( b*b - 4*a*c ) ) / ( 2*a ) what I typed is... >>> import math >>> math.sqrt(68*68-4*34*-510) 272.0 >>> (-68+sqrt(68*68-4*34*-510))/(2*34) but I keep getting Traceback (most recent call last): File "", line 1, in(-68+sqrt(68*68-4*34*-510))/(2*34) NameError: name 'sqrt' is not defined Can anyone help me with this and explain it? Thanks a lot. I am a beginner...
MIT 6.00 Intro Computer Science (OCW)
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
what were you expecting when you wrote "(-68+sqrt(68*68-4*34*-510))/(2*34)" ?
You either need to do: "from math import* if you don't want to type math.sqrt(2) and just say sqrt(2) or "from math import as m" so you could use m.sqrt(2). All I know is that how importing and using libraries works in python.
Hi thank you for your reply. When I wrote "(-68+sqrt(68*68-4*34*-510))/(2*34)" , I was expecting to get the final result.But I didn't get the final result, I got NameError: name 'sqrt' is not defined instead.