Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.0
I think they are asking for the vertex because they say the minimum OR maximum can you find the vertex?
 9 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
I dont understand how to
 9 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.0
I stink at explaining, but I have this http://www.algebra.com/algebra/homework/Rationalfunctions/Rationalfunctions.faq.question.501396.html you can also put in your equation ion the bottom and the solution will be given....
 9 months ago

ganibl Group TitleBest ResponseYou've already chosen the best response.1
Given equation is an expansion of (x  5)^2 with solution 5 so max value is 5
 9 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
can you explain how you got that
 9 months ago

ganibl Group TitleBest ResponseYou've already chosen the best response.1
(x 5)^2 = x^2  10x + 25 (a  b)^2 = a^2  2ab + b^2
 9 months ago

ganibl Group TitleBest ResponseYou've already chosen the best response.1
x  5 = 0 and x  5 = 0 x = 5 Which is the max value for the equation
 9 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
so what would be the vertex
 9 months ago

ganibl Group TitleBest ResponseYou've already chosen the best response.1
Min or max value of function is given by c = b^2/4a c = 100/4 = 25 which means the given function has minimum value of 25
 9 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.