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Baby-Nath24

  • 2 years ago

what is the min or max of y=x^2-10x+25

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  1. SolomonZelman
    • 2 years ago
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    I think they are asking for the vertex because they say the minimum OR maximum can you find the vertex?

  2. Baby-Nath24
    • 2 years ago
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    I dont understand how to

  3. SolomonZelman
    • 2 years ago
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    I stink at explaining, but I have this http://www.algebra.com/algebra/homework/Rational-functions/Rational-functions.faq.question.501396.html you can also put in your equation ion the bottom and the solution will be given....

  4. ganibl
    • 2 years ago
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    Given equation is an expansion of (x - 5)^2 with solution 5 so max value is 5

  5. Baby-Nath24
    • 2 years ago
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    can you explain how you got that

  6. ganibl
    • 2 years ago
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    (x -5)^2 = x^2 - 10x + 25 (a - b)^2 = a^2 - 2ab + b^2

  7. ganibl
    • 2 years ago
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    x - 5 = 0 and x - 5 = 0 x = 5 Which is the max value for the equation

  8. Baby-Nath24
    • 2 years ago
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    so what would be the vertex

  9. ganibl
    • 2 years ago
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    Min or max value of function is given by c = -b^2/4a c = -100/4 = -25 which means the given function has minimum value of -25

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