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anonymous
 2 years ago
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10.
A. 40
B. 10
C. 10
D. 399/40
anonymous
 2 years ago
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10. A. 40 B. 10 C. 10 D. 399/40

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0y=f(x). Take dy/dx ( f'(x) ) to get 20x+1. Critical points are where f'(x)=0. Solving: 0=20x+1 20x=1 x=1/20 y=f(x)=f(1/20)=9.975=399/40

ranga
 2 years ago
Best ResponseYou've already chosen the best response.0If you are in precalculus and have not been taught derivatives yet, put the equation in vertex form to find your min/max.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Looking at f(0) to the left of critical point (=10) and f(1) to the right (=19), you can tell that this point is a relative maximum. Because the parabola opens down, this is the 'biggest' the function can get (absolute maximum). You could have seen all of this from graphing the function.
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