Find the maximum or minimum of the following quadratic function: y = -10x^2 + x - 10. A. -40 B. -10 C. 10 D. -399/40

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Find the maximum or minimum of the following quadratic function: y = -10x^2 + x - 10. A. -40 B. -10 C. 10 D. -399/40

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Maximum = -399/40
1 Attachment
y=f(x). Take dy/dx ( f'(x) ) to get -20x+1. Critical points are where f'(x)=0. Solving: 0=-20x+1 20x=1 x=1/20 y=f(x)=f(1/20)=-9.975=-399/40
If you are in pre-calculus and have not been taught derivatives yet, put the equation in vertex form to find your min/max.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Looking at f(0) to the left of critical point (=-10) and f(1) to the right (=-19), you can tell that this point is a relative maximum. Because the parabola opens down, this is the 'biggest' the function can get (absolute maximum). You could have seen all of this from graphing the function.
Thanks Guys.

Not the answer you are looking for?

Search for more explanations.

Ask your own question