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BabyNath24
Group Title
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10.
A. 40
B. 10
C. 10
D. 399/40
 10 months ago
 10 months ago
BabyNath24 Group Title
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10. A. 40 B. 10 C. 10 D. 399/40
 10 months ago
 10 months ago

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voce Group TitleBest ResponseYou've already chosen the best response.0
Maximum = 399/40
 10 months ago

jlesaint Group TitleBest ResponseYou've already chosen the best response.0
y=f(x). Take dy/dx ( f'(x) ) to get 20x+1. Critical points are where f'(x)=0. Solving: 0=20x+1 20x=1 x=1/20 y=f(x)=f(1/20)=9.975=399/40
 10 months ago

ranga Group TitleBest ResponseYou've already chosen the best response.0
If you are in precalculus and have not been taught derivatives yet, put the equation in vertex form to find your min/max.
 10 months ago

jlesaint Group TitleBest ResponseYou've already chosen the best response.0
Looking at f(0) to the left of critical point (=10) and f(1) to the right (=19), you can tell that this point is a relative maximum. Because the parabola opens down, this is the 'biggest' the function can get (absolute maximum). You could have seen all of this from graphing the function.
 10 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
Thanks Guys.
 10 months ago
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