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 one year ago
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10.
A. 40
B. 10
C. 10
D. 399/40
 one year ago
Find the maximum or minimum of the following quadratic function: y = 10x^2 + x  10. A. 40 B. 10 C. 10 D. 399/40

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jlesaint
 one year ago
Best ResponseYou've already chosen the best response.0y=f(x). Take dy/dx ( f'(x) ) to get 20x+1. Critical points are where f'(x)=0. Solving: 0=20x+1 20x=1 x=1/20 y=f(x)=f(1/20)=9.975=399/40

ranga
 one year ago
Best ResponseYou've already chosen the best response.0If you are in precalculus and have not been taught derivatives yet, put the equation in vertex form to find your min/max.

jlesaint
 one year ago
Best ResponseYou've already chosen the best response.0Looking at f(0) to the left of critical point (=10) and f(1) to the right (=19), you can tell that this point is a relative maximum. Because the parabola opens down, this is the 'biggest' the function can get (absolute maximum). You could have seen all of this from graphing the function.
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