A community for students.
Here's the question you clicked on:
 0 viewing
bere1
 2 years ago
find the differential solution to the equation to which the given function is the general solution
y=(A+Bx+Cx^2)e^(2x)
bere1
 2 years ago
find the differential solution to the equation to which the given function is the general solution y=(A+Bx+Cx^2)e^(2x)

This Question is Closed

Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2I don't understand the question. What are we supposed to do?

Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2I guess, you want to find out the function? if so, from your general solution, I expand it to \(y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}\) that shows you have \(\lambda =2\) triple roots so, the characteristic equation is \((\lambda 2)^3 =0\) and then \(= \lambda^3 6\lambda^2+12\lambda 8 =0\) that gives us the original function is y''' 6y''+12y' 8y =0 that's all I know. Hope this help

bere1
 2 years ago
Best ResponseYou've already chosen the best response.0i figure it out thank you i was suppose to find the equation it was y'''6y''+8y'8y=0

bere1
 2 years ago
Best ResponseYou've already chosen the best response.0I just seen that thank you

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0Wow. Congrats on reaching \(\sf \color{limegreen}{green}\) status. You're now part of the elite.

Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2hihihi.... just stay so long in this site and get "green" . no smart, no knowledge
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.