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bere1
 one year ago
find the differential solution to the equation to which the given function is the general solution
y=(A+Bx+Cx^2)e^(2x)
bere1
 one year ago
find the differential solution to the equation to which the given function is the general solution y=(A+Bx+Cx^2)e^(2x)

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.2I don't understand the question. What are we supposed to do?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2I guess, you want to find out the function? if so, from your general solution, I expand it to \(y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}\) that shows you have \(\lambda =2\) triple roots so, the characteristic equation is \((\lambda 2)^3 =0\) and then \(= \lambda^3 6\lambda^2+12\lambda 8 =0\) that gives us the original function is y''' 6y''+12y' 8y =0 that's all I know. Hope this help

bere1
 one year ago
Best ResponseYou've already chosen the best response.0i figure it out thank you i was suppose to find the equation it was y'''6y''+8y'8y=0

bere1
 one year ago
Best ResponseYou've already chosen the best response.0I just seen that thank you

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Wow. Congrats on reaching \(\sf \color{limegreen}{green}\) status. You're now part of the elite.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2hihihi.... just stay so long in this site and get "green" . no smart, no knowledge
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