## bere1 find the differential solution to the equation to which the given function is the general solution y=(A+Bx+Cx^2)e^(2x) 2 months ago 2 months ago

1. Loser66

I don't understand the question. What are we supposed to do?

2. Loser66

I guess, you want to find out the function? if so, from your general solution, I expand it to $$y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}$$ that shows you have $$\lambda =2$$ triple roots so, the characteristic equation is $$(\lambda -2)^3 =0$$ and then $$= \lambda^3 -6\lambda^2+12\lambda -8 =0$$ that gives us the original function is y''' -6y''+12y' -8y =0 that's all I know. Hope this help

3. bere1

i figure it out thank you i was suppose to find the equation it was y'''-6y''+8y'-8y=0

4. Loser66

12y' , not 8y'

5. bere1

I just seen that thank you

6. Loser66

ok

7. abb0t

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8. Loser66

hihihi.... just stay so long in this site and get "green" . no smart, no knowledge