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anonymous
 2 years ago
find the differential solution to the equation to which the given function is the general solution
y=(A+Bx+Cx^2)e^(2x)
anonymous
 2 years ago
find the differential solution to the equation to which the given function is the general solution y=(A+Bx+Cx^2)e^(2x)

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Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2I don't understand the question. What are we supposed to do?

Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2I guess, you want to find out the function? if so, from your general solution, I expand it to \(y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}\) that shows you have \(\lambda =2\) triple roots so, the characteristic equation is \((\lambda 2)^3 =0\) and then \(= \lambda^3 6\lambda^2+12\lambda 8 =0\) that gives us the original function is y''' 6y''+12y' 8y =0 that's all I know. Hope this help

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i figure it out thank you i was suppose to find the equation it was y'''6y''+8y'8y=0

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I just seen that thank you

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0Wow. Congrats on reaching \(\sf \color{limegreen}{green}\) status. You're now part of the elite.

Loser66
 2 years ago
Best ResponseYou've already chosen the best response.2hihihi.... just stay so long in this site and get "green" . no smart, no knowledge
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