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bere1 Group Title

find the differential solution to the equation to which the given function is the general solution y=(A+Bx+Cx^2)e^(2x)

  • 8 months ago
  • 8 months ago

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  1. Loser66 Group Title
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    I don't understand the question. What are we supposed to do?

    • 8 months ago
  2. Loser66 Group Title
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    I guess, you want to find out the function? if so, from your general solution, I expand it to \(y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}\) that shows you have \(\lambda =2\) triple roots so, the characteristic equation is \((\lambda -2)^3 =0\) and then \(= \lambda^3 -6\lambda^2+12\lambda -8 =0\) that gives us the original function is y''' -6y''+12y' -8y =0 that's all I know. Hope this help

    • 8 months ago
  3. bere1 Group Title
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    i figure it out thank you i was suppose to find the equation it was y'''-6y''+8y'-8y=0

    • 8 months ago
  4. Loser66 Group Title
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    12y' , not 8y'

    • 8 months ago
  5. bere1 Group Title
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    I just seen that thank you

    • 8 months ago
  6. Loser66 Group Title
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    ok

    • 8 months ago
  7. abb0t Group Title
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    Wow. Congrats on reaching \(\sf \color{limegreen}{green}\) status. You're now part of the elite.

    • 8 months ago
  8. Loser66 Group Title
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    hihihi.... just stay so long in this site and get "green" . no smart, no knowledge

    • 8 months ago
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