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hoopshiree
 2 years ago
what is the value of b x^2+y^2+ax+by+c=0
hoopshiree
 2 years ago
what is the value of b x^2+y^2+ax+by+c=0

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helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1the value of \(b\) for what?

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0for that equation, \[x ^{2}+y ^{2^{}}+ax+by+c=0\]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1r u sure the question is exactly that? it kind of doesn't make sense

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0this graph is part of the question

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1u also need to find the values of a, b, and c so that the equation describes the circle of the figure. complete both squares. u know the center and the radius of the circle (see the graph)

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1do u know how to complete the square?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1ok i will do it. first the center is C(2,1) and r=3, do u agree?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1ok know, the equation of a circle should be \[\large (xh)^2+(yk)^2=r^2 \] we have to make the equation \[\large x^2+y^2ax+by+c=0 \] to resemble this. OK?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1\[\large x^2+y^2+ax+by+c=0 \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1we know that h=2, k=1, and r=3, agree?

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0(x+2)+(x+2)+(y1)+(y1)=9?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1no \[\large (x+2)^2+(y1)^2=3^2 \] \[\large (x^2+4x+4)+(y^22x+1)=9 \] \[\large x^2+y^2+4x2y+5=9 \] \[\large x^2+y^2+4x2y4=0 \]

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1no, b is the coefficient of \(y\)

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0can you help me with this one?

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0have to find a now. so the center is (1,3) and radius is 4 right?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0correction number one, the centre of circle is (1,2) not (2,1). so, h = 1 and k = 2 now remember the equation of circle is x^2 + y^2 +ax + by + c = 0 or (x  h)^2 + (y k)^2 = 0 h,k is the centre of circle. the relation of b and k is b = 1/2(k) so, b = 1/2(2) = 1

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1YES. I am so sorry, my mistake.

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1in the second case the center is (3,1) and r=4

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0correction again, im not a boy, but a father of that boy ;p

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0does A have a certain formula that can be used to find it?

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1dont learn formulas, learn concepts. do what i did before: expand \[\large (x3)^2+(y+1)^2=4^2 \] it should take a minute

SnuggieLad
 2 years ago
Best ResponseYou've already chosen the best response.0Welcome To Openstudy

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0so (x^26x+9)+(y^2+2x+1)=16?

hoopshiree
 2 years ago
Best ResponseYou've already chosen the best response.0so a would be = 3 1/2

helder_edwin
 2 years ago
Best ResponseYou've already chosen the best response.1a=6, that is what u got.

ranga
 2 years ago
Best ResponseYou've already chosen the best response.1It should be (x^26x+9)+(y^2+2y+1)=16 (you had 2x, it should be 2y). In bx^2+y^2+ax+by+c=0, a is the coefficient of x. The coefficient of x in the equation you got is 6 So a = 6.
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