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helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
the value of \(b\) for what?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
for that equation, \[x ^{2}+y ^{2^{}}+ax+by+c=0\]
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
@helder_edwin
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
r u sure the question is exactly that? it kind of doesn't make sense
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
this graph is part of the question
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
u also need to find the values of a, b, and c so that the equation describes the circle of the figure. complete both squares. u know the center and the radius of the circle (see the graph)
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
that doesnt help me
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
but thanks
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
do u know how to complete the square?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
ok i will do it. first the center is C(2,1) and r=3, do u agree?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
I got that far.
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
ok know, the equation of a circle should be \[\large (xh)^2+(yk)^2=r^2 \] we have to make the equation \[\large x^2+y^2ax+by+c=0 \] to resemble this. OK?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[\large x^2+y^2+ax+by+c=0 \]
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+2)^2+(y1)^2=3^2
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
we know that h=2, k=1, and r=3, agree?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
yes. expand that!
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
can u do it?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+2)+(x+2)+(y1)+(y1)=9?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
I'm so confuseddd.
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
no \[\large (x+2)^2+(y1)^2=3^2 \] \[\large (x^2+4x+4)+(y^22x+1)=9 \] \[\large x^2+y^2+4x2y+5=9 \] \[\large x^2+y^2+4x2y4=0 \]
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
got it?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so b is 4?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
no, b is the coefficient of \(y\)
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
can you help me with this one?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
same question?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
have to find a now. so the center is (1,3) and radius is 4 right?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+1)+(y3)=16?
 8 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
correction number one, the centre of circle is (1,2) not (2,1). so, h = 1 and k = 2 now remember the equation of circle is x^2 + y^2 +ax + by + c = 0 or (x  h)^2 + (y k)^2 = 0 h,k is the centre of circle. the relation of b and k is b = 1/2(k) so, b = 1/2(2) = 1
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
YES. I am so sorry, my mistake.
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
oh boy. okay.
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
in the second case the center is (3,1) and r=4
 8 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
correction again, im not a boy, but a father of that boy ;p
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
does A have a certain formula that can be used to find it?
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
dont learn formulas, learn concepts. do what i did before: expand \[\large (x3)^2+(y+1)^2=4^2 \] it should take a minute
 8 months ago

SnuggieLad Group TitleBest ResponseYou've already chosen the best response.0
Welcome To Openstudy
 8 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
a = 1/2 * h
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so (x^26x+9)+(y^2+2x+1)=16?
 8 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so a would be = 3 1/2
 8 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
a=6, that is what u got.
 8 months ago

ranga Group TitleBest ResponseYou've already chosen the best response.1
It should be (x^26x+9)+(y^2+2y+1)=16 (you had 2x, it should be 2y). In bx^2+y^2+ax+by+c=0, a is the coefficient of x. The coefficient of x in the equation you got is 6 So a = 6.
 8 months ago
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