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helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1the value of \(b\) for what?

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0for that equation, \[x ^{2}+y ^{2^{}}+ax+by+c=0\]

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1r u sure the question is exactly that? it kind of doesn't make sense

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0this graph is part of the question

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1u also need to find the values of a, b, and c so that the equation describes the circle of the figure. complete both squares. u know the center and the radius of the circle (see the graph)

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0that doesnt help me

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1do u know how to complete the square?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1ok i will do it. first the center is C(2,1) and r=3, do u agree?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1ok know, the equation of a circle should be \[\large (xh)^2+(yk)^2=r^2 \] we have to make the equation \[\large x^2+y^2ax+by+c=0 \] to resemble this. OK?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1\[\large x^2+y^2+ax+by+c=0 \]

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0(x+2)^2+(y1)^2=3^2

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1we know that h=2, k=1, and r=3, agree?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1yes. expand that!

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0(x+2)+(x+2)+(y1)+(y1)=9?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1no \[\large (x+2)^2+(y1)^2=3^2 \] \[\large (x^2+4x+4)+(y^22x+1)=9 \] \[\large x^2+y^2+4x2y+5=9 \] \[\large x^2+y^2+4x2y4=0 \]

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1no, b is the coefficient of \(y\)

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with this one?

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0have to find a now. so the center is (1,3) and radius is 4 right?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0correction number one, the centre of circle is (1,2) not (2,1). so, h = 1 and k = 2 now remember the equation of circle is x^2 + y^2 +ax + by + c = 0 or (x  h)^2 + (y k)^2 = 0 h,k is the centre of circle. the relation of b and k is b = 1/2(k) so, b = 1/2(2) = 1

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1YES. I am so sorry, my mistake.

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1in the second case the center is (3,1) and r=4

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0correction again, im not a boy, but a father of that boy ;p

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0does A have a certain formula that can be used to find it?

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1dont learn formulas, learn concepts. do what i did before: expand \[\large (x3)^2+(y+1)^2=4^2 \] it should take a minute

SnuggieLad
 one year ago
Best ResponseYou've already chosen the best response.0Welcome To Openstudy

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0so (x^26x+9)+(y^2+2x+1)=16?

hoopshiree
 one year ago
Best ResponseYou've already chosen the best response.0so a would be = 3 1/2

helder_edwin
 one year ago
Best ResponseYou've already chosen the best response.1a=6, that is what u got.

ranga
 one year ago
Best ResponseYou've already chosen the best response.1It should be (x^26x+9)+(y^2+2y+1)=16 (you had 2x, it should be 2y). In bx^2+y^2+ax+by+c=0, a is the coefficient of x. The coefficient of x in the equation you got is 6 So a = 6.
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