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helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
the value of \(b\) for what?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
for that equation, \[x ^{2}+y ^{2^{}}+ax+by+c=0\]
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
@helder_edwin
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
r u sure the question is exactly that? it kind of doesn't make sense
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
this graph is part of the question
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
u also need to find the values of a, b, and c so that the equation describes the circle of the figure. complete both squares. u know the center and the radius of the circle (see the graph)
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
that doesnt help me
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
but thanks
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
do u know how to complete the square?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
ok i will do it. first the center is C(2,1) and r=3, do u agree?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
I got that far.
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
ok know, the equation of a circle should be \[\large (xh)^2+(yk)^2=r^2 \] we have to make the equation \[\large x^2+y^2ax+by+c=0 \] to resemble this. OK?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[\large x^2+y^2+ax+by+c=0 \]
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+2)^2+(y1)^2=3^2
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
we know that h=2, k=1, and r=3, agree?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
yes. expand that!
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
can u do it?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+2)+(x+2)+(y1)+(y1)=9?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
I'm so confuseddd.
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
no \[\large (x+2)^2+(y1)^2=3^2 \] \[\large (x^2+4x+4)+(y^22x+1)=9 \] \[\large x^2+y^2+4x2y+5=9 \] \[\large x^2+y^2+4x2y4=0 \]
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
got it?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so b is 4?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
no, b is the coefficient of \(y\)
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
oh 2?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
can you help me with this one?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
same question?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
have to find a now. so the center is (1,3) and radius is 4 right?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
(x+1)+(y3)=16?
 11 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
correction number one, the centre of circle is (1,2) not (2,1). so, h = 1 and k = 2 now remember the equation of circle is x^2 + y^2 +ax + by + c = 0 or (x  h)^2 + (y k)^2 = 0 h,k is the centre of circle. the relation of b and k is b = 1/2(k) so, b = 1/2(2) = 1
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
YES. I am so sorry, my mistake.
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
oh boy. okay.
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
in the second case the center is (3,1) and r=4
 11 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
correction again, im not a boy, but a father of that boy ;p
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
does A have a certain formula that can be used to find it?
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
dont learn formulas, learn concepts. do what i did before: expand \[\large (x3)^2+(y+1)^2=4^2 \] it should take a minute
 11 months ago

SnuggieLad Group TitleBest ResponseYou've already chosen the best response.0
Welcome To Openstudy
 11 months ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
a = 1/2 * h
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so (x^26x+9)+(y^2+2x+1)=16?
 11 months ago

hoopshiree Group TitleBest ResponseYou've already chosen the best response.0
so a would be = 3 1/2
 11 months ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
a=6, that is what u got.
 11 months ago

ranga Group TitleBest ResponseYou've already chosen the best response.1
It should be (x^26x+9)+(y^2+2y+1)=16 (you had 2x, it should be 2y). In bx^2+y^2+ax+by+c=0, a is the coefficient of x. The coefficient of x in the equation you got is 6 So a = 6.
 11 months ago
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