anonymous
  • anonymous
Hey y'all! So I have a test tomorrow and really need help on this question! Please help me! The Centripetal acceleration of the satellite is approximately...
Physics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
And please explain why! :)
anonymous
  • anonymous
You know the equation for centrepedal acceleration? \[a=v^2/r\] here a is acceleration, v is velocity of the object, here satellite, r is the radius of circular motion, here R+h

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
what is h?
anonymous
  • anonymous
nvm lol but why r+h
anonymous
  • anonymous
Cause.. r is usually the distance from the CENTRE of the earth if the distance is faarrrr away.. like for example u were calculating acceleration of the earth revolving around sun, then we could neglect the size of the sun.. (150 million kilometer is way bigger than 0.7 million kilometers right?) but in ur problem, the altitude is comparable to the size of the earth.. infact smaller :P hence u need to consider the radius of earth!
Isaiah.Feynman
  • Isaiah.Feynman
Also...I would say since the acceleration acts towards the center of the circular path you would need to use r+h since the earth and the path are concentric (they share the same radius)

Looking for something else?

Not the answer you are looking for? Search for more explanations.