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kaylalynn
Show, using limits, that f(x)=x^2 -x +3, is continuous at x=2
Check if the left hand limit = right hand limit. If it is, then limit exists. Existence of limit at point a implies the function is continuous at point a.
Check if\[\lim_{x\rightarrow 2^+}f(x)=\lim_{x\rightarrow 2^-}f(x)\]
\[f(x)=\sin \frac{ 1 }{ x-1 }\]Use limits to determine if is continuous at x =1