Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mmorrison52

  • 2 years ago

Find the x-coordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^2-2x^5y=15. The derivative of that is [y(10x^2-3y)]/[2x(y-x^2)].

  • This Question is Open
  1. FutureMathProfessor
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You don't need the derivative. Just solve x^3y^2-2x^5y=15 for Y and where the function is undefined is your answer

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy