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mmorrison52

Find the x-coordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^2-2x^5y=15. The derivative of that is [y(10x^2-3y)]/[2x(y-x^2)].

  • 4 months ago
  • 4 months ago

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  1. FutureMathProfessor
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    You don't need the derivative. Just solve x^3y^2-2x^5y=15 for Y and where the function is undefined is your answer

    • 4 months ago
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