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Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].
 4 months ago
 4 months ago
Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].
 4 months ago
 4 months ago

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FutureMathProfessorBest ResponseYou've already chosen the best response.0
You don't need the derivative. Just solve x^3y^22x^5y=15 for Y and where the function is undefined is your answer
 4 months ago
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