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mmorrison52
 2 years ago
Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].
mmorrison52
 2 years ago
Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].

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FutureMathProfessor
 2 years ago
Best ResponseYou've already chosen the best response.0You don't need the derivative. Just solve x^3y^22x^5y=15 for Y and where the function is undefined is your answer
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