Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mmorrison52 Group Title

Find the x-coordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^2-2x^5y=15. The derivative of that is [y(10x^2-3y)]/[2x(y-x^2)].

  • one year ago
  • one year ago

  • This Question is Open
  1. FutureMathProfessor Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    You don't need the derivative. Just solve x^3y^2-2x^5y=15 for Y and where the function is undefined is your answer

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.