Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing
mmorrison52
Group Title
Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].
 9 months ago
 9 months ago
mmorrison52 Group Title
Find the xcoordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^22x^5y=15. The derivative of that is [y(10x^23y)]/[2x(yx^2)].
 9 months ago
 9 months ago

This Question is Open

FutureMathProfessor Group TitleBest ResponseYou've already chosen the best response.0
You don't need the derivative. Just solve x^3y^22x^5y=15 for Y and where the function is undefined is your answer
 9 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.