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goformit100
 one year ago
Best ResponseYou've already chosen the best response.0A warm Welcome to OpenStudy. I can help guide you through this useful site. You can ask your questions to me or you can message me. Please use the chat for off topic questions. Remember to give the person who helped you a medal by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/codeofconduct ). Please take a moment to read it.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Try substituting the bottom

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\frac{\sec^23x}{1+4\tan3x}~dx\] Let \(u=1+4\tan 3x\), so \(\dfrac{1}{12}du=\sec^23x~dx\): \[\frac{1}{12}\int\frac{du}{u}\]
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