Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
hanifah
Group Title
if a>0 what is the
lim(x>a) ((sqrt(2xa^3  x^4))  a(cuberoot((a^2)(x))))/(a(ax^3)^(1/4))
What method can help simplify this better? I started by multiplying top and bottom by the conjugate and it was still pretty messy. equation attached in comments for clarity. Any help would be appreciated! thanks
 10 months ago
 10 months ago
hanifah Group Title
if a>0 what is the lim(x>a) ((sqrt(2xa^3  x^4))  a(cuberoot((a^2)(x))))/(a(ax^3)^(1/4)) What method can help simplify this better? I started by multiplying top and bottom by the conjugate and it was still pretty messy. equation attached in comments for clarity. Any help would be appreciated! thanks
 10 months ago
 10 months ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Can we use L'hospital's rule?
 10 months ago

hanifah Group TitleBest ResponseYou've already chosen the best response.0
Yeah, I tried that first and got a very long/algebraic nightmare.. is it possible to multiply by the conjugate and then us lhr?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
lhospital is working for me
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
all you need is one round and then plug in
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
remember to treat a as constant
 10 months ago

Jonask Group TitleBest ResponseYou've already chosen the best response.2
using L'hospital's rule \[\Large \lim _{x\to a}\frac{\frac{2a^34x^3}{2(2ax^3x^4)^\frac{1}{2}}a\frac{a^2}{3(a^2x)^\frac {2}{3}}}{\frac{3ax^2}{4(ax^3)^\frac{3}{4}}}=\frac{a\frac{a}{3}}{\frac{3a^3}{4a^3}}=a\]
 10 months ago

hanifah Group TitleBest ResponseYou've already chosen the best response.0
ahhh, so I got the derivatives correct, but I simplified to something that is i don't even know.. haha. honest mistake that will probably kill me on the final=/.. giving the medal to @Jonask this round sorry @myininaya i appreciate the help though!!
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
4/3 divided by 3/4 is 16/9
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Also I didn't give you the answer because I wanted you to do it yourself. lol.
 10 months ago

hanifah Group TitleBest ResponseYou've already chosen the best response.0
i know.. @myininaya i'm guessing you're a teacher? haha joking.. jonask doesn't have a medal also I'm not entirely sure what the rules of openstudy are.. i just ask questions, but i feel like some people take the medals pretty seriously. I will sleep on it and get back to you :P
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
No I don't care about the medals. I just want the students to be able to get the answers themselves. This isn't suppose to be a site when you can come to cheat.
 10 months ago

Jonask Group TitleBest ResponseYou've already chosen the best response.2
yes ...the answer shud be 16a/9...since this was a messy job i decided to write the solution wich u obviously attemted...hence u cud see your mistake
 10 months ago

hanifah Group TitleBest ResponseYou've already chosen the best response.0
agree, i couldn't figure out where i messed up via wolfram so open study is the next best thing. i need to improve my algebra
 10 months ago

Jonask Group TitleBest ResponseYou've already chosen the best response.2
yes you are write,thats a good idea ,wolfram can help you only if you know ur algebra already,u jus need it for verification and visualisation...we should sharpen ourselves first before we use machines
 10 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.