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BabyNath24
Group Title
Solve the inequality: x^2  5x + 6 ≥ 0.
A. x ≤ 2 or x ≥ 3
B. 2 ≤ x ≤ 3
C. x ≤ or x ≥ 6
D. x ≤ 6 or x ≥ 1
 10 months ago
 10 months ago
BabyNath24 Group Title
Solve the inequality: x^2  5x + 6 ≥ 0. A. x ≤ 2 or x ≥ 3 B. 2 ≤ x ≤ 3 C. x ≤ or x ≥ 6 D. x ≤ 6 or x ≥ 1
 10 months ago
 10 months ago

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arbershabani97 Group TitleBest ResponseYou've already chosen the best response.0
(x3)(x2)= x^25x+6, do you need more help?
 10 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
Yeah.
 10 months ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[x ^{2}5x+6>0,x ^{2}5x>6\] adding both sides \[\left( \frac{ 5 }{ 2 } \right)^{2} i.e.,\frac{ 25 }{ 4 }\] \[x ^{2}5x+\frac{ 25 }{4 }>6+\frac{ 25 }{4 }\] \[\left( x\frac{ 5 }{ 2 } \right)^{2}>\frac{ 1 }{ 4 },\left x\frac{ 5 }{2 } \right>\frac{ 1 }{ 2 }\] solve it. \[(\left xa \right>b means xa <b and xa >b)\]
 10 months ago

arbershabani97 Group TitleBest ResponseYou've already chosen the best response.0
(x3)(x2)>=0 (its equal or greater than, but didn't know how to do the sign) x3>=0 and x2>=0 just solve for x and see in which one it is right
 10 months ago

BabyNath24 Group TitleBest ResponseYou've already chosen the best response.0
Oh ok thank you!!
 10 months ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[correction everywhere write \ge inplace of >\]
 10 months ago
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