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BabyNath24
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An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = 16t^2 + 64t + 80?
A. 272
B. 144
C. 1232
D. 616
 8 months ago
 8 months ago
BabyNath24 Group Title
An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = 16t^2 + 64t + 80? A. 272 B. 144 C. 1232 D. 616
 8 months ago
 8 months ago

This Question is Closed

xxferrocixx Group TitleBest ResponseYou've already chosen the best response.0
find the y value of the vertex
 8 months ago

monokerous Group TitleBest ResponseYou've already chosen the best response.0
First, find t, using the vertex formula \[b \over 2a\], then, plug in your answer t=? into the equation to find the height.
 8 months ago
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