## Baby-Nath24 one year ago An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t^2 + 64t + 80? A. 272 B. 144 C. 1232 D. 616

1. xxferrocixx

find the y value of the vertex

2. monokerous

First, find t, using the vertex formula $-b \over 2a$, then, plug in your answer t=? into the equation to find the height.