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Baby-Nath24

  • 2 years ago

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the object's maximum height if the equation of height (h) in terms of time (t) of the object is given by h(t) = -16t^2 + 64t + 80? A. 272 B. 144 C. 1232 D. 616

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  1. xxferrocixx
    • 2 years ago
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    find the y value of the vertex

  2. monokerous
    • 2 years ago
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    First, find t, using the vertex formula \[-b \over 2a\], then, plug in your answer t=? into the equation to find the height.

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