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It is copied correctly; a 3 term sum.

Have you copies it correctly or is Y^4 + (1/2) (y^2) + (1/16)(6^4)?

Does the middle term have the variable y^2 in it?

O.K. I was thinking of a perfect square, but now I see that I was on the wrong track.

there is a typo in your question somewhere for sure

\[ y^2+\frac{1}{4}y^2=\frac{5}{4}y^2\] once you combine like terms

I have since corrected it; thank you.

still a typo, since \((\frac{5}{4}y^2)^2=\frac{25}{16}y^4\)

Sorry again; I didn't see the missing parentheses. Now it is corrected(knock on wood);)

oooh now i get it
\[\left(y^2+\frac{1}{4y^2}\right)^2\]

happy holidaze! you done?

probably easiest to see if you multiply out and see that it works

yw (from all of us)

I hope you all have a great happy holiday! :)