How to factor y^4+1/2+1/(16y^4)?
I know that it factors into (y^2+1/(4y^2))^2, but I can't figure out why.
I need to simplify this for an arc length integral. Any help is greatly appreciated.

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It is copied correctly; a 3 term sum.

Have you copies it correctly or is Y^4 + (1/2) (y^2) + (1/16)(6^4)?

Does the middle term have the variable y^2 in it?

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