How to factor y^4+1/2+1/(16y^4)?
I know that it factors into (y^2+1/(4y^2))^2, but I can't figure out why.
I need to simplify this for an arc length integral. Any help is greatly appreciated.

See more answers at brainly.com

It is copied correctly; a 3 term sum.

Have you copies it correctly or is Y^4 + (1/2) (y^2) + (1/16)(6^4)?

Does the middle term have the variable y^2 in it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.