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What should I do after that? Add those two equations together?

You will have a system of equations to solve just like from algebra class.

Well I got, 4a - 10 = 4b - 6 and then -32 + 5 = 4b - 3. Is that correct?

I mean equation err

oops you are right.

\[a(2)^4+5(2)=b(2)^2-3(2) \text{ first equation }\]

\[4a(2)^3+5=2b(2)-3 \text{ second equation }\]

Wait isn't it a(-2)^4 + 5 (-2) since the limit is coming from the left side?

It isn't approaching -2. It is approaching 2.

Ahh ok I got it :) After I get these 2 equations then what should I do afterward?

Have you ever solved a system of two linear equations?

Yes, like 4 years ago haha.

16a + 10
4b - 6
32a + 5
4b - 3 ( Can't I just substitute it and then solve it) ?

Do you think you can rewrite equation 2 in that form?

32a - 4b = -8 ( 2nd equation right) right?

looks good

So we have
16a-4b=-16
32a-4b=-8

I'm trying to eliminate b. (you could go for a but I prefer working with smaller numbers)

So
-16a+4b=16
32a-4b=-8
----------------add the equations together and what do we get?

I got the final answer of 6 for b. Is that right?

and .5 for a

yep. good job.

yayyy, you should just be my tutor haha. Thank you so much :D

np