>>> a_list = [3,5,6,12]
>>> new_list = 
>>> for x in a_list:
if x % 2 == 0:
if x % 2 != 0:
Anyone know why this won't work in Python shell? Trying to get a Boolean list from an integer list printed like this: [True, True, False, False]. I have gotten only:
This is question 7 on the Handout for OCW, ex. 2.12 of a 6.189 Gentle Intro to Python. Any insight appreciated. I am going on day 5 of not getting this. . . .
MIT 6.189 A Gentle Introduction to Programming Using Python (OCW)
Stacey Warren - Expert brainly.com
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go into the python shell and type help(list.append) i feel this will help you immensely with what you are trying to accomplish
as a side note, you can type help(any built in object) into the python shell and you will get a list of all the methods(functions the object can do) for that object along with a quick description of how they work
When you print the values, it does not add them to your list. It just prints the values.
If you say `newlist = True` that also does not add `True` to the list, rather it discards the list. What you want to do is `list.append(True)` to add a Boolean to the list.
In addition, the `==` operator returns a Boolean result.
Thus simply putting `newlist.append(x % 2 == 0)` will fit your needs.
The best way to convert one list to another in python is to use list comprehension:
newlist = [ func(x) for x in oldlist ]
Where `func` takes some argument, changes it in some way, and returns the result.
For example, if you want to change an integer into a Boolean value based on whether it is even
return x % 2 == 0
Then you would say:
newlist = [iseven(x) for x in oldlist]