A community for students.
Here's the question you clicked on:
 0 viewing
 one year ago
differential equation using classical method. assume zero condition.
anybody can give exact solution?
1.) d^2x/dt^2 + 8 dx/dt+ 25x = 10 u(t)
2.)d^2x/dt^2 + 2 dx/dt+ x = 5e−2t + t
3.)d^2x/dt^2 + 4x = t2
 one year ago
differential equation using classical method. assume zero condition. anybody can give exact solution? 1.) d^2x/dt^2 + 8 dx/dt+ 25x = 10 u(t) 2.)d^2x/dt^2 + 2 dx/dt+ x = 5e−2t + t 3.)d^2x/dt^2 + 4x = t2

This Question is Open

douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.0These are similar to differential equations in physics with acceleration (d2y/dt^2) and a resistance term (dy/dt). start with y =A exp(kt) and see what you get.

jayven
 one year ago
Best ResponseYou've already chosen the best response.0nope in physics..it is also about laplace.

douglaswinslowcooper
 one year ago
Best ResponseYou've already chosen the best response.0I was never good at Laplace transforms. Often they are listed in books such as STANDARD MATHEMATICAL TABLES. My recollection is that you use the transform to convert the diff eqn into a polynomial, solve it to some degree, then use the inverse transform to get the answer. Did it decades ago, and not well!

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0The "Classical" method is NOT Laplace. Find the Characteristic Equation and solve for the homogeneous solution. Add the particular solution. Then you have a lot of algebra in your future.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0is u(t) the unit step function?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.