A community for students.
Here's the question you clicked on:
 0 viewing
on.vlp
 2 years ago
Help me please !!!!!
I have f(x) = 6x  x^2  6sqrt(a+b)
determine: (f(sqrt(a+b)  f(1)) / sqrt(a+b) = ?
Thank you for your help
on.vlp
 2 years ago
Help me please !!!!! I have f(x) = 6x  x^2  6sqrt(a+b) determine: (f(sqrt(a+b)  f(1)) / sqrt(a+b) = ? Thank you for your help

This Question is Open

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[f(\sqrt{a+b})=6\sqrt{a+b}(\sqrt{a+b})^26\sqrt{a+b} \]

on.vlp
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=6xx ^{2}6\sqrt{a+b} \]

on.vlp
 2 years ago
Best ResponseYou've already chosen the best response.0but i need to find: \[\frac{ f(\sqrt{a+b})f(1) }{ \sqrt{a+b}}=?\]

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Yes I'm asking you to find that one thing first.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Just simplify what I wrote above and we are going to plug that into your expression that you are trying to evaluate

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1387347305923:dw This is our main goal to evaluate But right now I'm having you work on the little parts of it first like this circled thing:

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1387347352551:dw

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1then we will find this other circled thing: dw:1387347373389:dw

on.vlp
 2 years ago
Best ResponseYou've already chosen the best response.0it's clear thank you very much myininaya
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.