Here's the question you clicked on:
ThatGuyInTheBack
Out of genuine curiosity, does d/dx of x^x=x^x?
My logic is that d/dx(x^x)= (x)(x^(x-1))= x^((x-1)+1)= x^x
\[y=x^x \] Use log diff: First step take log of both sides: \[\ln(y)=\ln(x^x) => \ln(y) =x \ln(x) \] Now differentiate both sides: Then solve for y'
Anyways, I can finish the problem if you want
I don't want to waste any more of your time. You answered my curiosity, and that's all I needed. Thank you very much.