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ThatGuyInTheBack
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Out of genuine curiosity, does d/dx of x^x=x^x?
 8 months ago
 8 months ago
ThatGuyInTheBack Group Title
Out of genuine curiosity, does d/dx of x^x=x^x?
 8 months ago
 8 months ago

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ThatGuyInTheBack Group TitleBest ResponseYou've already chosen the best response.0
My logic is that d/dx(x^x)= (x)(x^(x1))= x^((x1)+1)= x^x
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[y=x^x \] Use log diff: First step take log of both sides: \[\ln(y)=\ln(x^x) => \ln(y) =x \ln(x) \] Now differentiate both sides: Then solve for y'
 8 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Anyways, I can finish the problem if you want
 8 months ago

ThatGuyInTheBack Group TitleBest ResponseYou've already chosen the best response.0
I don't want to waste any more of your time. You answered my curiosity, and that's all I needed. Thank you very much.
 8 months ago
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