ThatGuyInTheBack Group Title Out of genuine curiosity, does d/dx of x^x=x^x? 8 months ago 8 months ago

1. ThatGuyInTheBack Group Title

My logic is that d/dx(x^x)= (x)(x^(x-1))= x^((x-1)+1)= x^x

2. myininaya Group Title

$y=x^x$ Use log diff: First step take log of both sides: $\ln(y)=\ln(x^x) => \ln(y) =x \ln(x)$ Now differentiate both sides: Then solve for y'

3. myininaya Group Title

Anyways, I can finish the problem if you want

4. ThatGuyInTheBack Group Title

I don't want to waste any more of your time. You answered my curiosity, and that's all I needed. Thank you very much.

5. myininaya Group Title

Np.