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Diamond_Swag11
Group Title
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign?
A.
64 ft2
B.
196 ft2
C.
112 ft2
D.
256 ft2
 10 months ago
 10 months ago
Diamond_Swag11 Group Title
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
 10 months ago
 10 months ago

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Diamond_Swag11 Group TitleBest ResponseYou've already chosen the best response.0
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
 10 months ago

chitters Group TitleBest ResponseYou've already chosen the best response.0
a length of 14 feet and a perimeter of 44 feet means that your width can be obtained with a perimeter function: perimeter is a function of length and width p(l, w) 2l + 2w = p(l, w) 2(14) + 2w = 44 = p(14, w) 28 + 2w = 44 2w = 44  28 2w = 16 w = 8 so if you have a new square with a width of 8 the value of its area is the function: a(w) = w^2 a(8) = (8)^2 a(8) = 64 so your area will be 64 ft squared
 10 months ago
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