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Diamond_Swag11
Group Title
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign?
A.
64 ft2
B.
196 ft2
C.
112 ft2
D.
256 ft2
 8 months ago
 8 months ago
Diamond_Swag11 Group Title
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
 8 months ago
 8 months ago

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Diamond_Swag11 Group TitleBest ResponseYou've already chosen the best response.0
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
 8 months ago

chitters Group TitleBest ResponseYou've already chosen the best response.0
a length of 14 feet and a perimeter of 44 feet means that your width can be obtained with a perimeter function: perimeter is a function of length and width p(l, w) 2l + 2w = p(l, w) 2(14) + 2w = 44 = p(14, w) 28 + 2w = 44 2w = 44  28 2w = 16 w = 8 so if you have a new square with a width of 8 the value of its area is the function: a(w) = w^2 a(8) = (8)^2 a(8) = 64 so your area will be 64 ft squared
 8 months ago
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