anonymous
  • anonymous
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
A rectangular sign had a perimeter of 44 feet and a length of 14 feet. A designer shortened the length so that the sign became a square with the same width as the old sign. What was the area of the new sign? A. 64 ft2 B. 196 ft2 C. 112 ft2 D. 256 ft2
anonymous
  • anonymous
a length of 14 feet and a perimeter of 44 feet means that your width can be obtained with a perimeter function: perimeter is a function of length and width p(l, w) 2l + 2w = p(l, w) 2(14) + 2w = 44 = p(14, w) 28 + 2w = 44 2w = 44 - 28 2w = 16 w = 8 so if you have a new square with a width of 8 the value of its area is the function: a(w) = w^2 a(8) = (8)^2 a(8) = 64 so your area will be 64 ft squared

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