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RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
put x in evidence
 10 months ago

atlas Group TitleBest ResponseYou've already chosen the best response.2
Another way of thinking is divide the expression on R.H.S with x^2 and then multiply it with x^2 on the outside
 10 months ago

atlas Group TitleBest ResponseYou've already chosen the best response.2
multiplying and dividing Right hand side with x^2 \[\frac{ x ^{2}(x+dx)^{2} }{ x^{2} }\] \[x^{2} (\frac{ x+dx }{ x })^{2}\]
 10 months ago

atlas Group TitleBest ResponseYou've already chosen the best response.2
simplify it to x^2 (1+dx/x)^2 I hope it makes sense now
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
I stiil dont get it Could someone please explain it step by step?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Ok, do you agree that x+dx could be written as x(1+dx/x)?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x+dx=x+\frac{x}{x} dx=x+x \cdot \frac{dx}{x}=x(1+\frac{dx}{x})\]
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
how can x+dx be written as x(1+dx/x)?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[(x+dx)^{2}=[(x)(1+\frac{dx}{x})]^{2}=x^{2}(1+\frac{dx}{x})^{2} \]
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Did you see what I said above what you said?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
dw:1387637203504:dw
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
dw:1387637215111:dw
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you can factor out that x
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
but how did you get to x+x d/x? the equation is (x+dx)^2
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You wanted step by step I'm looking at the inside, x+dx, right now.
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
If you can understand why x+dx=x(1+dx/x) we can move on to the exponent part
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
which i already did above
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
but i can redo
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
i dont understand why x+dx=x(1+dx/x)
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
where did you get the 1?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Like do you the distributive property. It says: a(b+c)=ab+ac
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
and how did you get dx/x?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x+dx=x+\frac{x}{x} dx \] look I multiply dx by x/x which is just one
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you should see an x in both terms now
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you can factor an x out
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
how did you get x/x?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x(1+\frac{1}{x}dx)\] \[x(1+\frac{dx}{x}) \]
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
I just put it there so you would see better x/x is there if you write it because it is just one
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
If you factor something out you are dividing the terms you factor from
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
im sorry but i dont understnad
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
*understand
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
For example \[3x+9=3(\frac{3x}{3}+\frac{9}{3})=3(x+3)\] Do you understand this example?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
Can you please write down every step you do and how you get every variable?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
in one answer please
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
If you don't understand it separately how do you expect to understand it together?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Do you understand the example I just put?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
no sorry
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
im new to calculus
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You might want to review factoring then. Because all I did was factor 3x+9 in that example
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
i will
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Do you know the distributive property?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
no sorry
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Like a(b+c) means ab+ac
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
That is the distributive property
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
You can look at it either way. a(b+c)=ab+ac ab+ac=a(b+c) Do you see on this side they say hey both of these terms have an a in common so let's factor it out
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
What they are doing when they factor is pulling something out (multiplying) and then also dividing by what they pulled out. Like for example , ab+ac we could factor factor out ac but that means we also need to divide each term by ac like this: \[ac(\frac{ab}{ac}+\frac{ac}{ac})=ac(\frac{b}{c}+1)\]
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
What do you get when you multiply out the ac(b/c+1) expression?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i must go good luck
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
no idea
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
thankyou
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
I don't understand what we are supposed to do, re read your post, y +dy = (x+dx)^2 equal = x^2(1+dx/x)^2 can you use the draw box below to write it again ?
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
and dy =y'? dx =x'?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
\[y+dy=(x+dx)^{2} =x ^{2}(1+\frac{ dx }{ x })^{2}\]
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
the aim is to differentiate y=x^2
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
2 equal signs?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
the second equal sign is the result
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
once we have powered the left hand side of the equation to 2
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
what do you mean by "ODE?"
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
one more question: from which course , you have this problem?
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
its from a book called calculus made easy, ill post the page i found it on right now
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
thanks for information,
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
no problem
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
ill post the page in a sec
 10 months ago

Bryanluxor Group TitleBest ResponseYou've already chosen the best response.0
he adds dy or dx to expand it a bit
 10 months ago

OOOPS Group TitleBest ResponseYou've already chosen the best response.0
I can understand (x +dx)^(2) = x^(2)(1+dx/x)^2 but from y +dy , I cannot see how they get the right hand side. since y = x^2 > dy = 2x^3 y + dy = x^2  2 x^3 = x^2(12dx/x) which is not their right hand side :((
 10 months ago

zpupster Group TitleBest ResponseYou've already chosen the best response.0
this might clear it up i like this book his proofs are easier to understand than the way was taught.
 10 months ago
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