Luigi0210
Find the 3rd term in:
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Luigi0210
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\[\LARGE (x+y)^4\]
shamil98
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The 3 term?
shamil98
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Clarify on what you're asking please =)
myininaya
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I think he means to find the third term when putting (x+y)^4 in standard descending expanded form.
Luigi0210
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Yea, that ^
shamil98
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(x+y)(x+y)(x+y)(x+y)
er, (x+y) ?
myininaya
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Yep multiplying it all out.
But there is a shortcut.
Luigi0210
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You learned this in Alg II/trig/pre-calc sham :)
shamil98
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Just wanted to be sure what he was asking xD
shamil98
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it seemed to easy lol.
thought it was a trick question o-o
myininaya
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You could use pascal's triangle or the binomial theorem
shamil98
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\[(x+y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4\]
shamil98
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third term is 6x^2y^2
myininaya
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\[(a+b)^n=\left(\begin{matrix}n \\ 0\end{matrix}\right)a^na^0+\left(\begin{matrix} n \\ 1\end{matrix}\right)a^{n-1}b^1+\cdots +\left(\begin{matrix}n \\ k\end{matrix}\right)a^{n-k} b^k+\cdots \left(\begin{matrix}n \\ n\end{matrix}\right)a^0b^n\]
where that one term that has all the k's is the k+1 term.
undeadknight26
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I has a question what is the difference between the diamond shaped smart score, the purple smart score and the green smart score?
Kainui
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What's the form of a polynomial who's "pascal triangle" has the form::
|dw:1387987847972:dw|
Luigi0210
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I was actually looking for the method that myin mention but others work too :)
Thanks everyone!
shamil98
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diamond shaped = they sponsor (subscription to OS)
shamil98
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purple = moderator
shamil98
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green smart score = 90 or higher
Our unofficial title is lord
Luigi0210
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^Yup
undeadknight26
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oh cool beans...i liked the orange though...lol...
shamil98
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the days of the orange war are long gone :')
Luigi0210
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.. for now