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shamil98
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\[\text{Find}~ f_{xxyzz}~ \text{for} f(x,y,z) = z^4y^3 \ln x\]
is this right :
\[f_x = \frac{ z^4y^3 }{ x }\]
\[f_{xx} = \frac{ z^4y^3 }{ x^2 }\]
\[f_{xxy} = \frac{ 3z^4y^2 }{ x^2 }\]
\[f_{xxyz} = \frac{ 12z^3y^2 }{ x^2 }\]
\[f_{xxyzz} = \frac{ 36z^2y^2 }{ x^2 }\]
 11 months ago
 11 months ago
shamil98 Group Title
\[\text{Find}~ f_{xxyzz}~ \text{for} f(x,y,z) = z^4y^3 \ln x\] is this right : \[f_x = \frac{ z^4y^3 }{ x }\] \[f_{xx} = \frac{ z^4y^3 }{ x^2 }\] \[f_{xxy} = \frac{ 3z^4y^2 }{ x^2 }\] \[f_{xxyz} = \frac{ 12z^3y^2 }{ x^2 }\] \[f_{xxyzz} = \frac{ 36z^2y^2 }{ x^2 }\]
 11 months ago
 11 months ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.2
wouldn't you start by finding fz first ?
 11 months ago

shamil98 Group TitleBest ResponseYou've already chosen the best response.1
the problem itself is asking for \[f_{xxyzz}\] the first part is \[f_x\]
 11 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
the final answer would be same, but your method is incorrect
 11 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
no, dw:1388132091438:dw
 11 months ago

shamil98 Group TitleBest ResponseYou've already chosen the best response.1
so the first part would be: \[f_z = 4z^3y^3 \ln x\]
 11 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yes, continue that way ....and you'll get the same final answer :)
 11 months ago

shamil98 Group TitleBest ResponseYou've already chosen the best response.1
alright, ty :)
 11 months ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
welcome ^_^
 11 months ago
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