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shamil98

  • one year ago

\[\text{Find}~ f_{xxyzz}~ \text{for} f(x,y,z) = z^4y^3 \ln x\] is this right : \[f_x = \frac{ z^4y^3 }{ x }\] \[f_{xx} = -\frac{ z^4y^3 }{ x^2 }\] \[f_{xxy} = -\frac{ 3z^4y^2 }{ x^2 }\] \[f_{xxyz} = -\frac{ 12z^3y^2 }{ x^2 }\] \[f_{xxyzz} = -\frac{ 36z^2y^2 }{ x^2 }\]

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  1. hartnn
    • one year ago
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    wouldn't you start by finding fz first ?

  2. shamil98
    • one year ago
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    the problem itself is asking for \[f_{xxyzz}\] the first part is \[f_x\]

  3. hartnn
    • one year ago
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    the final answer would be same, but your method is incorrect

  4. hartnn
    • one year ago
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    no, |dw:1388132091438:dw|

  5. shamil98
    • one year ago
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    oh.

  6. shamil98
    • one year ago
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    so the first part would be: \[f_z = 4z^3y^3 \ln x\]

  7. hartnn
    • one year ago
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    yes, continue that way ....and you'll get the same final answer :)

  8. shamil98
    • one year ago
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    alright, ty :)

  9. hartnn
    • one year ago
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    welcome ^_^

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