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anonymous
 3 years ago
write each polar equation in rectangular form:
r=3sec(Theta)
r=costheta+sintheta
r=5/3costheta+8sin
anonymous
 3 years ago
write each polar equation in rectangular form: r=3sec(Theta) r=costheta+sintheta r=5/3costheta+8sin

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0^theta after the last sin

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1You need to use these equations: \[r^2=x^2+y^2 ; rcos(\theta)=x ; rsin(\theta)=y \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i did, but like it ended up like x^2+y^2= 25+9x^2r^230xr/64y^2 for the last one

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1We want the equations just in terms of x and y instead of r and theta.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i don't know what i did wrong

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1so the last one is: \[r=\frac{5}{3}\cos(\theta)+8\sin(\theta) \]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no uh (5)/(3costheta+8sintheta)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1oh so you meant 5/(3costheta)+8sin(theta)) and not 5/3cos(theta)+8sin(theta)

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[r= \frac{5}{3\cos(\theta)+8\sin(\theta)}\] Multiply both sides by that one fraction's denominator

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1\[r(3\cos(\theta)+8\sin(\theta))=5 \] Distribute then substitute the equations I gave you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.03xr+8ry=5 but then you'll need to put r on one side cause you would need to square it. and the answer comes out all weird

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1well rcos(theta) is x not just cos(theta same thing with the y deal rsin(theta) is y not just sin(theta)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0whoops how about the secant one

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1put it in terms of cos by using an identity

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1then put it in some form where you can use the equations I gave you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sosoososososo it would be x^3+y^2x=3 AND uh the other one x^2+y^2=x+y?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1for the first one? no...

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1I haven't looked at the second one... You are making this way too hard it looks like.

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1first one you did this as first step right?: \[r=\frac{3}{\cos(\theta)}\]

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Notice this only has a cos in it... how do you get cos with the r over there so you can use the equation rcos(theta)=x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0multiply both sides with r

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1How do you undo multiplication?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1we have division by cos to undo that you ?

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1so for that second one...

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1you actually got it right

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1but how did you go about it you didn't choose a complicated way right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yep uh multiplied both side with r and then substituted the stuff in

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1do you have any other questions? do you think you got this better?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0uh yea i have a few more

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for standard forms of polar equation uh how would graph r=2cos3theta

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1Plug in values of theta and see what the r output is

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1then remember how you graph using polar coordinates r is the distance from the origin and direction is given by r to from the angle theta is the angle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like how would you do this with a graphing calculator

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1So for example if I plug in theta=0 \[r=2 \cos (3 \cdot 0)=2\cos(0)=2(1)=2 => \text{ graph the point } (2,0^o)\] dw:1388269865874:dw

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1find 0 degrees and then go to the circle with radius 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cause wksht says not to use a table

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1388269927627:dw then plug in more points

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i know how to graph but not without plugging in points

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1I haven't looked at a calculator in ages

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1did you try looking up how to input polar equations into whatever calculator type you have

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1some calculators require a difference procedure in order to do certain things

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1http://mathbits.com/MathBits/TISection/PreCalculus/polargraphs.htm

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1find mode and choose polar or pol or polargc

myininaya
 3 years ago
Best ResponseYou've already chosen the best response.1then just type your equation in
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