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write each polar equation in rectangular form:
r=3sec(Theta)
r=costheta+sintheta
r=5/3costheta+8sin
 3 months ago
 3 months ago
write each polar equation in rectangular form: r=3sec(Theta) r=costheta+sintheta r=5/3costheta+8sin
 3 months ago
 3 months ago

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musicdramalife00Best ResponseYou've already chosen the best response.0
^theta after the last sin
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
You need to use these equations: \[r^2=x^2+y^2 ; rcos(\theta)=x ; rsin(\theta)=y \]
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
i did, but like it ended up like x^2+y^2= 25+9x^2r^230xr/64y^2 for the last one
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
We want the equations just in terms of x and y instead of r and theta.
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
i don't know what i did wrong
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
so the last one is: \[r=\frac{5}{3}\cos(\theta)+8\sin(\theta) \]?
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
no uh (5)/(3costheta+8sintheta)
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
oh so you meant 5/(3costheta)+8sin(theta)) and not 5/3cos(theta)+8sin(theta)
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
mhm 5 / (3cos+8sin)
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
\[r= \frac{5}{3\cos(\theta)+8\sin(\theta)}\] Multiply both sides by that one fraction's denominator
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
\[r(3\cos(\theta)+8\sin(\theta))=5 \] Distribute then substitute the equations I gave you
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
3xr+8ry=5 but then you'll need to put r on one side cause you would need to square it. and the answer comes out all weird
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
well rcos(theta) is x not just cos(theta same thing with the y deal rsin(theta) is y not just sin(theta)
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
whoops how about the secant one
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
put it in terms of cos by using an identity
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
then put it in some form where you can use the equations I gave you
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
sosoososososo it would be x^3+y^2x=3 AND uh the other one x^2+y^2=x+y?
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
for the first one? no...
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
I haven't looked at the second one... You are making this way too hard it looks like.
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
first one you did this as first step right?: \[r=\frac{3}{\cos(\theta)}\]
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
Notice this only has a cos in it... how do you get cos with the r over there so you can use the equation rcos(theta)=x
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
multiply both sides with r
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
How do you undo multiplication?
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
we have division by cos to undo that you ?
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
so for that second one...
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
you actually got it right
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
but how did you go about it you didn't choose a complicated way right?
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
yep uh multiplied both side with r and then substituted the stuff in
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
do you have any other questions? do you think you got this better?
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
uh yea i have a few more
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
for standard forms of polar equation uh how would graph r=2cos3theta
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
Plug in values of theta and see what the r output is
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
then remember how you graph using polar coordinates r is the distance from the origin and direction is given by r to from the angle theta is the angle
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
like how would you do this with a graphing calculator
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
So for example if I plug in theta=0 \[r=2 \cos (3 \cdot 0)=2\cos(0)=2(1)=2 => \text{ graph the point } (2,0^o)\] dw:1388269865874:dw
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
find 0 degrees and then go to the circle with radius 2
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
cause wksht says not to use a table
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
dw:1388269927627:dw then plug in more points
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
oh i know how to graph but not without plugging in points
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
I haven't looked at a calculator in ages
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
did you try looking up how to input polar equations into whatever calculator type you have
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
some calculators require a difference procedure in order to do certain things
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
http://mathbits.com/MathBits/TISection/PreCalculus/polargraphs.htm
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
find mode and choose polar or pol or polargc
 3 months ago

myininayaBest ResponseYou've already chosen the best response.1
then just type your equation in
 3 months ago

musicdramalife00Best ResponseYou've already chosen the best response.0
u what's the website
 3 months ago
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