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musicdramalife00 Group Title

write each polar equation in rectangular form: r=-3sec(Theta) r=costheta+sintheta r=5/3costheta+8sin

  • 7 months ago
  • 7 months ago

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  1. musicdramalife00 Group Title
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    ^theta after the last sin

    • 7 months ago
  2. myininaya Group Title
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    You need to use these equations: \[r^2=x^2+y^2 ; rcos(\theta)=x ; rsin(\theta)=y \]

    • 7 months ago
  3. musicdramalife00 Group Title
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    i did, but like it ended up like x^2+y^2= 25+9x^2r^2-30xr/64y^2 for the last one

    • 7 months ago
  4. myininaya Group Title
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    We want the equations just in terms of x and y instead of r and theta.

    • 7 months ago
  5. musicdramalife00 Group Title
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    i don't know what i did wrong

    • 7 months ago
  6. myininaya Group Title
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    so the last one is: \[r=\frac{5}{3}\cos(\theta)+8\sin(\theta) \]?

    • 7 months ago
  7. musicdramalife00 Group Title
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    no uh (5)/(3costheta+8sintheta)

    • 7 months ago
  8. myininaya Group Title
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    oh so you meant 5/(3costheta)+8sin(theta)) and not 5/3cos(theta)+8sin(theta)

    • 7 months ago
  9. musicdramalife00 Group Title
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    mhm 5 / (3cos+8sin)

    • 7 months ago
  10. myininaya Group Title
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    \[r= \frac{5}{3\cos(\theta)+8\sin(\theta)}\] Multiply both sides by that one fraction's denominator

    • 7 months ago
  11. myininaya Group Title
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    \[r(3\cos(\theta)+8\sin(\theta))=5 \] Distribute then substitute the equations I gave you

    • 7 months ago
  12. musicdramalife00 Group Title
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    3xr+8ry=5 but then you'll need to put r on one side cause you would need to square it. and the answer comes out all weird

    • 7 months ago
  13. myininaya Group Title
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    well rcos(theta) is x not just cos(theta same thing with the y deal rsin(theta) is y not just sin(theta)

    • 7 months ago
  14. musicdramalife00 Group Title
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    whoops how about the secant one

    • 7 months ago
  15. myininaya Group Title
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    put it in terms of cos by using an identity

    • 7 months ago
  16. myininaya Group Title
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    then put it in some form where you can use the equations I gave you

    • 7 months ago
  17. musicdramalife00 Group Title
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    sosoososososo it would be x^3+y^2x=-3 AND uh the other one x^2+y^2=x+y?

    • 7 months ago
  18. myininaya Group Title
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    for the first one? no...

    • 7 months ago
  19. myininaya Group Title
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    I haven't looked at the second one... You are making this way too hard it looks like.

    • 7 months ago
  20. myininaya Group Title
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    first one you did this as first step right?: \[r=\frac{-3}{\cos(\theta)}\]

    • 7 months ago
  21. musicdramalife00 Group Title
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    yep

    • 7 months ago
  22. myininaya Group Title
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    Notice this only has a cos in it... how do you get cos with the r over there so you can use the equation rcos(theta)=x

    • 7 months ago
  23. musicdramalife00 Group Title
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    multiply both sides with r

    • 7 months ago
  24. myininaya Group Title
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    no

    • 7 months ago
  25. myininaya Group Title
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    try again

    • 7 months ago
  26. myininaya Group Title
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    How do you undo multiplication?

    • 7 months ago
  27. myininaya Group Title
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    Or division?

    • 7 months ago
  28. musicdramalife00 Group Title
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    oh omg

    • 7 months ago
  29. myininaya Group Title
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    we have division by cos to undo that you ?

    • 7 months ago
  30. musicdramalife00 Group Title
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    x=-3

    • 7 months ago
  31. myininaya Group Title
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    yes

    • 7 months ago
  32. musicdramalife00 Group Title
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    thanks

    • 7 months ago
  33. myininaya Group Title
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    so for that second one...

    • 7 months ago
  34. myininaya Group Title
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    you actually got it right

    • 7 months ago
  35. myininaya Group Title
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    but how did you go about it you didn't choose a complicated way right?

    • 7 months ago
  36. musicdramalife00 Group Title
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    yep uh multiplied both side with r and then substituted the stuff in

    • 7 months ago
  37. myininaya Group Title
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    oh good

    • 7 months ago
  38. myininaya Group Title
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    do you have any other questions? do you think you got this better?

    • 7 months ago
  39. musicdramalife00 Group Title
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    uh yea i have a few more

    • 7 months ago
  40. musicdramalife00 Group Title
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    for standard forms of polar equation uh how would graph r=2cos3theta

    • 7 months ago
  41. myininaya Group Title
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    Plug in values of theta and see what the r output is

    • 7 months ago
  42. myininaya Group Title
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    then remember how you graph using polar coordinates r is the distance from the origin and direction is given by r to from the angle theta is the angle

    • 7 months ago
  43. musicdramalife00 Group Title
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    like how would you do this with a graphing calculator

    • 7 months ago
  44. myininaya Group Title
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    So for example if I plug in theta=0 \[r=2 \cos (3 \cdot 0)=2\cos(0)=2(1)=2 => \text{ graph the point } (2,0^o)\] |dw:1388269865874:dw|

    • 7 months ago
  45. myininaya Group Title
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    find 0 degrees and then go to the circle with radius 2

    • 7 months ago
  46. musicdramalife00 Group Title
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    cause wksht says not to use a table

    • 7 months ago
  47. myininaya Group Title
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    |dw:1388269927627:dw| then plug in more points

    • 7 months ago
  48. musicdramalife00 Group Title
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    oh i know how to graph but not without plugging in points

    • 7 months ago
  49. myininaya Group Title
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    I haven't looked at a calculator in ages

    • 7 months ago
  50. myininaya Group Title
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    did you try looking up how to input polar equations into whatever calculator type you have

    • 7 months ago
  51. myininaya Group Title
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    some calculators require a difference procedure in order to do certain things

    • 7 months ago
  52. myininaya Group Title
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    http://mathbits.com/MathBits/TISection/PreCalculus/polargraphs.htm

    • 7 months ago
  53. myininaya Group Title
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    find mode and choose polar or pol or polargc

    • 7 months ago
  54. myininaya Group Title
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    then just type your equation in

    • 7 months ago
  55. musicdramalife00 Group Title
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    u what's the website

    • 7 months ago
  56. musicdramalife00 Group Title
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    *uh

    • 7 months ago
  57. myininaya Group Title
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    What ?

    • 7 months ago
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