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 11 months ago
write each polar equation in rectangular form:
r=3sec(Theta)
r=costheta+sintheta
r=5/3costheta+8sin
 11 months ago
write each polar equation in rectangular form: r=3sec(Theta) r=costheta+sintheta r=5/3costheta+8sin

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musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0^theta after the last sin

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1You need to use these equations: \[r^2=x^2+y^2 ; rcos(\theta)=x ; rsin(\theta)=y \]

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0i did, but like it ended up like x^2+y^2= 25+9x^2r^230xr/64y^2 for the last one

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1We want the equations just in terms of x and y instead of r and theta.

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0i don't know what i did wrong

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1so the last one is: \[r=\frac{5}{3}\cos(\theta)+8\sin(\theta) \]?

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0no uh (5)/(3costheta+8sintheta)

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1oh so you meant 5/(3costheta)+8sin(theta)) and not 5/3cos(theta)+8sin(theta)

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0mhm 5 / (3cos+8sin)

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1\[r= \frac{5}{3\cos(\theta)+8\sin(\theta)}\] Multiply both sides by that one fraction's denominator

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1\[r(3\cos(\theta)+8\sin(\theta))=5 \] Distribute then substitute the equations I gave you

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.03xr+8ry=5 but then you'll need to put r on one side cause you would need to square it. and the answer comes out all weird

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1well rcos(theta) is x not just cos(theta same thing with the y deal rsin(theta) is y not just sin(theta)

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0whoops how about the secant one

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1put it in terms of cos by using an identity

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1then put it in some form where you can use the equations I gave you

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0sosoososososo it would be x^3+y^2x=3 AND uh the other one x^2+y^2=x+y?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1for the first one? no...

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1I haven't looked at the second one... You are making this way too hard it looks like.

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1first one you did this as first step right?: \[r=\frac{3}{\cos(\theta)}\]

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1Notice this only has a cos in it... how do you get cos with the r over there so you can use the equation rcos(theta)=x

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0multiply both sides with r

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1How do you undo multiplication?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1we have division by cos to undo that you ?

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1so for that second one...

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1you actually got it right

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1but how did you go about it you didn't choose a complicated way right?

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0yep uh multiplied both side with r and then substituted the stuff in

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1do you have any other questions? do you think you got this better?

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0uh yea i have a few more

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0for standard forms of polar equation uh how would graph r=2cos3theta

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1Plug in values of theta and see what the r output is

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1then remember how you graph using polar coordinates r is the distance from the origin and direction is given by r to from the angle theta is the angle

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0like how would you do this with a graphing calculator

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1So for example if I plug in theta=0 \[r=2 \cos (3 \cdot 0)=2\cos(0)=2(1)=2 => \text{ graph the point } (2,0^o)\] dw:1388269865874:dw

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1find 0 degrees and then go to the circle with radius 2

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0cause wksht says not to use a table

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1dw:1388269927627:dw then plug in more points

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0oh i know how to graph but not without plugging in points

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1I haven't looked at a calculator in ages

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1did you try looking up how to input polar equations into whatever calculator type you have

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1some calculators require a difference procedure in order to do certain things

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1http://mathbits.com/MathBits/TISection/PreCalculus/polargraphs.htm

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1find mode and choose polar or pol or polargc

myininaya
 11 months ago
Best ResponseYou've already chosen the best response.1then just type your equation in

musicdramalife00
 11 months ago
Best ResponseYou've already chosen the best response.0u what's the website
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