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anonymous
 2 years ago
What is the inverse of f if….
anonymous
 2 years ago
What is the inverse of f if….

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(3) \sqrt[3]{x2}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\sqrt[3]{x2}\] ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(3)=\sqrt[3]{x2}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i forgot to put an = sign the first time

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0are we finding f'(3) either way to get the inverse, let's replace f(x) with y \[y = \sqrt[3]{x2}\] switch x and y \[x = \sqrt[3]{y2}\] cube both sides \[x^3 = {y2}\] \[x^3+2=y\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^{3}+2=y^{3}\] is that right?.. i have no idea I'm so stressed

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0How'd you get y^3? Remember that square roots and squares are inverse operations, right? \[(\sqrt{x})^2 = x\] \[(\sqrt[3]{x})^3 = x\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh i got confused i thought you said for ME to cube both sides lol. I'm sorry I'm extremely tired and have to get a bunch of work done by like tomorrow. ughhh. my bad

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0lol no worries, just always go over your work a bazillion times so that you can prove to yourself that your answer is right. ANYHOW, the inverse is now f(x) =x^2+2 f(3) = 3^2+2 = ??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0wait so the answer is f(x) =x^2+2 ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0whoops./ you generally say inverse with a little dash f'(x) so the equation for the inverse is f'(x) = x^2 + 2 then you plug in 3 into the inverse equation (assuming that's the question)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0heres the actual question with the answer choices so you can see

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0god damn. I kept saying x^2 +2 but I meant x^3 + 2

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hahah so is it the 3rd option then?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0thank youuu! i have another question! do you mind helping me??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0are you gonna post it here or make a new question? I don't mind

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ill post it here! and thanks! (:

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0uh you'd multiply by the conjugate. pardon my handwriting

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0to simplify radicals you multiply by the conjugate pair which means flipping the sign

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0why do you have that answer selected?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0what do you mean that answer selected?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0what are the answer choices?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the ones with the bubble next to them on the link i posted!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0rofl I didn't see it scrolled down a bit.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hahahah its all good! (:

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so what is the answer?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Perform the operation bibby suggested and then simplify.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0you can use wolfram if you don't like learning http://www.wolframalpha.com/input/?i=%28sqrt%283%29sqrt%286%29%29%2F%28sqrt%283%29%2Bsqrt%286%29%29

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0its not that i don't like learning its that i am in a hurry and i have no idea whats going on.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{3}\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}\sqrt{6}}{\sqrt{3}\sqrt{6}}\] Do this multiplication here.

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Why are you in a hurry? Is this a test?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i had to go out of town so I'm behind on a bunch of work due like really soon

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1So you don't know how to multiply something like this (a+b)(c+d)?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1A lot of Americans like to use this thing called the foil method.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i have heard of it but idk how to really use it

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1(a+b)(c+d)=ac+ad+bc+bd

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0all you did was distribute those right?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1388451041982:dw

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1yepdw:1388451059969:dw

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1(a+b)(c+d)=a(c+d)+b(c+d) =ac+ad+bc+bd

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1So if you had \[(\sqrt{3}\sqrt{6})(\sqrt{3}\sqrt{6})\] what do you have after multiplying?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0idk how to group square roots together or multiply them together

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Do that foil method then we will work on simplifying

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hold on its gonna take awhile to plug in

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1You don't have to use what I gave you as a formula. Just distribute. Take each of the terms in the first grouping and multiply to each term in the second grouping

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh wow my computer plugged in the wrong numbers so thats not even the right question, this is the right question...

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Well I will show you how to do the first one and you try this one.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i tried solving it and i think its the second answer choice

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{3}\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}\sqrt{6}}{\sqrt{3}\sqrt{6}}\] This was the operation you were asked to perform. I was having you look at the numerator first. So looking at the numerator if we multiply the top out we would get: \[\frac{\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{6}\sqrt{6} \sqrt{3}+\sqrt{6} \sqrt{6}}{(\sqrt{3}+\sqrt{6})(\sqrt{3}\sqrt{6})}\]

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1Do you see how I got that top part?

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1If a, b>=0 then \[\sqrt{a} \cdot \sqrt{b} =\sqrt{a \cdot b} \]

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1so basically \[\sqrt{3} \cdot \sqrt{3} =3 \text{ and } \sqrt{3} \cdot \sqrt{6}=\sqrt{18}=\sqrt{9 \cdot 2} =\sqrt{9} \cdot \sqrt{2}=3\sqrt{2}\]

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1combine like terms on top and multiply the bottom out i have to go for now

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0This has to be the longest problem eve

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0ever* lol my name is eve:P

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hahaha hey eve! and yah i know…i have a lot of stuff i need help withhh ughh

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0not mch jst listening to music i was about to leave lol
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