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bibby
 one year ago
Best ResponseYou've already chosen the best response.3\[f(x)=\sqrt[3]{x2}\] ?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1i forgot to put an = sign the first time

bibby
 one year ago
Best ResponseYou've already chosen the best response.3are we finding f'(3) either way to get the inverse, let's replace f(x) with y \[y = \sqrt[3]{x2}\] switch x and y \[x = \sqrt[3]{y2}\] cube both sides \[x^3 = {y2}\] \[x^3+2=y\]

emma97
 one year ago
Best ResponseYou've already chosen the best response.1\[x^{3}+2=y^{3}\] is that right?.. i have no idea I'm so stressed

bibby
 one year ago
Best ResponseYou've already chosen the best response.3How'd you get y^3? Remember that square roots and squares are inverse operations, right? \[(\sqrt{x})^2 = x\] \[(\sqrt[3]{x})^3 = x\]

emma97
 one year ago
Best ResponseYou've already chosen the best response.1oh i got confused i thought you said for ME to cube both sides lol. I'm sorry I'm extremely tired and have to get a bunch of work done by like tomorrow. ughhh. my bad

bibby
 one year ago
Best ResponseYou've already chosen the best response.3lol no worries, just always go over your work a bazillion times so that you can prove to yourself that your answer is right. ANYHOW, the inverse is now f(x) =x^2+2 f(3) = 3^2+2 = ??

emma97
 one year ago
Best ResponseYou've already chosen the best response.1wait so the answer is f(x) =x^2+2 ?

bibby
 one year ago
Best ResponseYou've already chosen the best response.3whoops./ you generally say inverse with a little dash f'(x) so the equation for the inverse is f'(x) = x^2 + 2 then you plug in 3 into the inverse equation (assuming that's the question)

emma97
 one year ago
Best ResponseYou've already chosen the best response.1heres the actual question with the answer choices so you can see

bibby
 one year ago
Best ResponseYou've already chosen the best response.3god damn. I kept saying x^2 +2 but I meant x^3 + 2

emma97
 one year ago
Best ResponseYou've already chosen the best response.1hahah so is it the 3rd option then?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1thank youuu! i have another question! do you mind helping me??

bibby
 one year ago
Best ResponseYou've already chosen the best response.3are you gonna post it here or make a new question? I don't mind

emma97
 one year ago
Best ResponseYou've already chosen the best response.1ill post it here! and thanks! (:

bibby
 one year ago
Best ResponseYou've already chosen the best response.3uh you'd multiply by the conjugate. pardon my handwriting

bibby
 one year ago
Best ResponseYou've already chosen the best response.3to simplify radicals you multiply by the conjugate pair which means flipping the sign

bibby
 one year ago
Best ResponseYou've already chosen the best response.3why do you have that answer selected?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1what do you mean that answer selected?

bibby
 one year ago
Best ResponseYou've already chosen the best response.3what are the answer choices?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1the ones with the bubble next to them on the link i posted!

bibby
 one year ago
Best ResponseYou've already chosen the best response.3rofl I didn't see it scrolled down a bit.

emma97
 one year ago
Best ResponseYou've already chosen the best response.1hahahah its all good! (:

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Perform the operation bibby suggested and then simplify.

bibby
 one year ago
Best ResponseYou've already chosen the best response.3you can use wolfram if you don't like learning http://www.wolframalpha.com/input/?i=%28sqrt%283%29sqrt%286%29%29%2F%28sqrt%283%29%2Bsqrt%286%29%29

emma97
 one year ago
Best ResponseYou've already chosen the best response.1its not that i don't like learning its that i am in a hurry and i have no idea whats going on.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{3}\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}\sqrt{6}}{\sqrt{3}\sqrt{6}}\] Do this multiplication here.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Why are you in a hurry? Is this a test?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1i had to go out of town so I'm behind on a bunch of work due like really soon

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1So you don't know how to multiply something like this (a+b)(c+d)?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1A lot of Americans like to use this thing called the foil method.

emma97
 one year ago
Best ResponseYou've already chosen the best response.1i have heard of it but idk how to really use it

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1(a+b)(c+d)=ac+ad+bc+bd

emma97
 one year ago
Best ResponseYou've already chosen the best response.1all you did was distribute those right?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1dw:1388451041982:dw

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1yepdw:1388451059969:dw

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1(a+b)(c+d)=a(c+d)+b(c+d) =ac+ad+bc+bd

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1So if you had \[(\sqrt{3}\sqrt{6})(\sqrt{3}\sqrt{6})\] what do you have after multiplying?

emma97
 one year ago
Best ResponseYou've already chosen the best response.1idk how to group square roots together or multiply them together

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Do that foil method then we will work on simplifying

emma97
 one year ago
Best ResponseYou've already chosen the best response.1hold on its gonna take awhile to plug in

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1You don't have to use what I gave you as a formula. Just distribute. Take each of the terms in the first grouping and multiply to each term in the second grouping

emma97
 one year ago
Best ResponseYou've already chosen the best response.1oh wow my computer plugged in the wrong numbers so thats not even the right question, this is the right question...

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Well I will show you how to do the first one and you try this one.

emma97
 one year ago
Best ResponseYou've already chosen the best response.1i tried solving it and i think its the second answer choice

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{3}\sqrt{6}}{\sqrt{3}+\sqrt{6}} \cdot \frac{\sqrt{3}\sqrt{6}}{\sqrt{3}\sqrt{6}}\] This was the operation you were asked to perform. I was having you look at the numerator first. So looking at the numerator if we multiply the top out we would get: \[\frac{\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{6}\sqrt{6} \sqrt{3}+\sqrt{6} \sqrt{6}}{(\sqrt{3}+\sqrt{6})(\sqrt{3}\sqrt{6})}\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Do you see how I got that top part?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1If a, b>=0 then \[\sqrt{a} \cdot \sqrt{b} =\sqrt{a \cdot b} \]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1so basically \[\sqrt{3} \cdot \sqrt{3} =3 \text{ and } \sqrt{3} \cdot \sqrt{6}=\sqrt{18}=\sqrt{9 \cdot 2} =\sqrt{9} \cdot \sqrt{2}=3\sqrt{2}\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1combine like terms on top and multiply the bottom out i have to go for now

Chooch146
 one year ago
Best ResponseYou've already chosen the best response.1This has to be the longest problem eve

Chooch146
 one year ago
Best ResponseYou've already chosen the best response.1ever* lol my name is eve:P

emma97
 one year ago
Best ResponseYou've already chosen the best response.1hahaha hey eve! and yah i know…i have a lot of stuff i need help withhh ughh

Chooch146
 one year ago
Best ResponseYou've already chosen the best response.1not mch jst listening to music i was about to leave lol
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