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\[f(3) \sqrt[3]{x-2}\]

\[f(x)=\sqrt[3]{x-2}\]
?

\[f(3)=\sqrt[3]{x-2}\]

i forgot to put an = sign the first time

\[x^{3}+2=y^{3}\] is that right?.. i have no idea I'm so stressed

wait so the answer is f(x) =x^2+2 ?

heres the actual question with the answer choices so you can see

god damn. I kept saying x^2 +2 but I meant x^3 + 2

hahah so is it the 3rd option then?

it is, it is...

thank youuu! i have another question! do you mind helping me??

are you gonna post it here or make a new question? I don't mind

ill post it here! and thanks! (:

i dont understand...

to simplify radicals you multiply by the conjugate pair which means flipping the sign

why do you have that answer selected?

what do you mean that answer selected?

what are the answer choices?

the ones with the bubble next to them on the link i posted!

rofl I didn't see it scrolled down a bit.

hahahah its all good! (:

so what is the answer?

Perform the operation bibby suggested and then simplify.

its not that i don't like learning its that i am in a hurry and i have no idea whats going on.

Why are you in a hurry? Is this a test?

idk how to..

i had to go out of town so I'm behind on a bunch of work due like really soon

So you don't know how to multiply something like this (a+b)(c+d)?

A lot of Americans like to use this thing called the foil method.

i have heard of it but idk how to really use it

(a+b)(c+d)=ac+ad+bc+bd

all you did was distribute those right?

|dw:1388451041982:dw|

yep|dw:1388451059969:dw|

(a+b)(c+d)=a(c+d)+b(c+d)
=ac+ad+bc+bd

So if you had \[(\sqrt{3}-\sqrt{6})(\sqrt{3}-\sqrt{6})\]
what do you have after multiplying?

idk how to group square roots together or multiply them together

Do that foil method then we will work on simplifying

hold on its gonna take awhile to plug in

oh wow my computer plugged in the wrong numbers so thats not even the right question, this is the right question...

Well I will show you how to do the first one and you try this one.

i tried solving it and i think its the second answer choice

Do you see how I got that top part?

yes

If a, b>=0 then \[\sqrt{a} \cdot \sqrt{b} =\sqrt{a \cdot b} \]

combine like terms on top
and multiply the bottom out
i have to go for now

ok.

This has to be the longest problem eve

ever*
lol my name is eve:P

hahaha hey eve! and yah i know…i have a lot of stuff i need help withhh ughh

Hai!

hahah whats up!

not mch jst listening to music i was about to leave lol

hahaha ok then! lol

bye