Confusionist
  • Confusionist
Can someone help me solve this? cos(x^2+45)+tan(4x+90) = sin(3x+120) A step by step would be great.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
by solving do you mean proving?
Confusionist
  • Confusionist
Yes. :)
myininaya
  • myininaya
What methods have been discussed?

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myininaya
  • myininaya
We are solving for x not proving this. This isn't an identity.
myininaya
  • myininaya
Or does it say to disprove or prove?
Confusionist
  • Confusionist
Ah yes, my bad. It says solve.
myininaya
  • myininaya
Can you tell me what methods in class have been discussed?
Confusionist
  • Confusionist
None, this is from a book with only problems I picked up at barnes and noble. We haven't done this and wont do it for another year or two. I've had no problems with the book up to this point.
myininaya
  • myininaya
can you tell me what methods the book has discussed?
Confusionist
  • Confusionist
None. It's a book of only problems. It starts from Geometry and works it's way up in problems.
myininaya
  • myininaya
Name of book please
Confusionist
  • Confusionist
Math Review for the High School Classroom
Confusionist
  • Confusionist
I looked for it online and can't find it.
myininaya
  • myininaya
I didn't see the book. :( So there are no examples?
Confusionist
  • Confusionist
No examples, just questions. :c How did you learn it?
myininaya
  • myininaya
Honestly, I don't know without seeing some example or them mentioning some method they want to use.
Confusionist
  • Confusionist
Ah, okay. Thanks, anyway. :)
shamil98
  • shamil98
cos(x^2+45)+tan(4x+90) = sin(3x+120) cos(x^2+45)+sin/cos(4x+90) = sin(3x+120) dividing everything by sin. tan(x^2+45) + sec(4x+90) = 3x + 120 i don't remember trig that well, but you can convert it to this i think.
myininaya
  • myininaya
You can't do that... Like you can't divide by the trig part The trig part is a function not a number or variable on its own
shamil98
  • shamil98
oh
primeralph
  • primeralph
Are the angles in radians or degrees?
primeralph
  • primeralph
I'll assume degrees for now.
Confusionist
  • Confusionist
Degrees, yeah. ^^
hartnn
  • hartnn
45,90,120 suggest they are in degrees... we can convert sin and cos in tan, like cos A = tan (sqrt (1-A^2)/A) something like this and then use tan A+tan B formula...... but if thats possible, the algebra is going to be very ugly....
myininaya
  • myininaya
but @hartnn tan(90) does not exist you were talking about the sum identity for tan right?
primeralph
  • primeralph
@myininaya tan(a+90) = -1/tan(a), since they're perpendicular.
hartnn
  • hartnn
not tan(A+B) tan A +tan B , where B = 4x+90 and yeah, tan (A+90) = - cot 90 so maybe convert cos into cot and use cotA-cotB formula... i don't think that will be of any use though....
primeralph
  • primeralph
|dw:1388481204906:dw|
myininaya
  • myininaya
I don't like the x squared part much.
primeralph
  • primeralph
Series solution is what I'd prefer to us,e but not without an attempt with standard algera.
myininaya
  • myininaya
or maybe the whole problem i don't see how to do it with algebra/trig He said it was for high school though
hartnn
  • hartnn
even wolf doesn't give integral or rational solutions...
Confusionist
  • Confusionist
Yes, I'm a junior in high school, but the book said High School. It extends way past what I expect to learn in High School, though. I think they may have the age range a bit messed up.
primeralph
  • primeralph
No simple way to solve at that level.
myininaya
  • myininaya
@primeralph if you want, can you show me your series thing you were talking about? You know if you want to.
Confusionist
  • Confusionist
I might just go and ask one of the professors at the college I intern at. Thanks for your help, guys. :)
primeralph
  • primeralph
First I'd have to convert all to radians.
primeralph
  • primeralph
Then find a way to represent the equation as a DE, or simply use the Taylor power series.
myininaya
  • myininaya
what is equivalent to a (1 radian) squared? That bugs me. The little square there.
myininaya
  • myininaya
What I'm saying is I'm not used to looking at angles being squared
primeralph
  • primeralph
|dw:1388481895287:dw|
primeralph
  • primeralph
@myininaya Yeah I understand, but you'd have to extend your thinking beyond expecting trig to only apply to angles.
primeralph
  • primeralph
It will be extensive, but in the end, there might be real solutions.
myininaya
  • myininaya
x^2 and 45 will have different units
myininaya
  • myininaya
we have x^2=a^2 (degs)^2 and 45 is just in degs not degs^2
primeralph
  • primeralph
The x^2 term will be set to have some correction factor. After taking a look at it, I think it's solvable algebraically. It's just long.
primeralph
  • primeralph
And with a lot of restrictions to be imposed.
hartnn
  • hartnn
those ugly solutions http://www.wolframalpha.com/input/?i=cos%28x%5E2%2B45%29%2Btan%284x%2B90%29+%3D+sin%283x%2B120%29&dataset=
primeralph
  • primeralph
Don't think you used radians. Wolfram is radians by default.
hartnn
  • hartnn
doesn't make much difference http://www.wolframalpha.com/input/?i=cos%28x%5E2%2Bpi%2F4%29%2Btan%284x%2Bpi%2F2%29+%3D+sin%283x%2B2pi%2F3%29
myininaya
  • myininaya
wolfram doesn't want to solve it this is the way input it cos((x deg)^2+45 deg)+tan(4x deg+90 deg)=sin(3x deg+120 deg) http://www.wolframalpha.com/input/?i=cos%28%28x+deg%29%5E2%2B45+deg%29%2Btan%284x+deg%2B90+deg%29%3Dsin%283x+deg%2B120+deg%29
myininaya
  • myininaya
Maybe it doesn't like the unlike units being added either idk

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