• theEric
Hi! I'm looking at an example from my book and I'm hoping somebody can explain this. It's in the first chapter, but I don't want to skip out on anything. Thanks! Here is the issue: My book says that $$\dfrac{dp/dt}{p-900}=\dfrac{1}{2}$$ where $$p\neq 900$$. Theennn... "By the chain rule the left side of [that equation] is the derivative of $$\ln\left|p-900\right|$$ with respect to $$t$$, so we have $$\dfrac{d}{dt} \ln\left| p-900\right|=\dfrac{1}{2}$$" My issue is that I'm missing something. I see that $$\cancel{\dfrac{d}{dt}\dfrac{1}{p-900}= \ln \left| p-900\right|}$$.
Differential Equations

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