Hi! I'm looking at an example from my book and I'm hoping somebody can explain this. It's in the first chapter, but I don't want to skip out on anything. Thanks! Here is the issue:
My book says that \(\dfrac{dp/dt}{p-900}=\dfrac{1}{2}\) where \(p\neq 900\). Theennn... "By the chain rule the left side of [that equation] is the derivative of \(\ln\left|p-900\right|\) with respect to \(t\), so we have
\(\dfrac{d}{dt} \ln\left| p-900\right|=\dfrac{1}{2}\)"
My issue is that I'm missing something. I see that \(\cancel{\dfrac{d}{dt}\dfrac{1}{p-900}= \ln \left| p-900\right|}\).

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

I crossed that out because it's really \(\dfrac{1}{p-900}=\dfrac{d}{dt}\ln\left| p-900\right|\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.