Here's the question you clicked on:
Emily778
check for extraneous solutions. (x+3)^1/2-1=x Please show me step by step on how to do this. Thankyou.
is this your question? \[\frac{ (x+3)^1 }{ 2-1 }=x\]
No. It's shown exactly as I wrote it.
\[(x+3)^{\frac{ 1 }{ 2 }}-1=x\]
√(x+3) - 1 = x √(x+3) = x+1 x+3 = (x+1)^2 x+3 = x^2 + 2x + 1 0 = x^2 + x - 2 Quadratic Equation: x = ( -1±√(1^2 - 4(-2)) ) / 2 x = (-1±3)/2 x=1 OR x=-2 Check by plugging in: √(1+3) - 1 = 1 2-1=1 Correct √(-2+3) - 1 = -2 1-1 = -2 Incorrect Therefore: x=1 only
is that all? jeez, thanks Lol