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Emily778

  • 2 years ago

check for extraneous solutions. (x+3)^1/2-1=x Please show me step by step on how to do this. Thankyou.

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  1. ASAAD123
    • 2 years ago
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    is this your question? \[\frac{ (x+3)^1 }{ 2-1 }=x\]

  2. Emily778
    • 2 years ago
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    No. It's shown exactly as I wrote it.

  3. Emily778
    • 2 years ago
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    |dw:1388894942412:dw|

  4. nikato
    • 2 years ago
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    \[(x+3)^{\frac{ 1 }{ 2 }}-1=x\]

  5. Emily778
    • 2 years ago
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    yes lol

  6. Krazete
    • 2 years ago
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    √(x+3) - 1 = x √(x+3) = x+1 x+3 = (x+1)^2 x+3 = x^2 + 2x + 1 0 = x^2 + x - 2 Quadratic Equation: x = ( -1±√(1^2 - 4(-2)) ) / 2 x = (-1±3)/2 x=1 OR x=-2 Check by plugging in: √(1+3) - 1 = 1 2-1=1 Correct √(-2+3) - 1 = -2 1-1 = -2 Incorrect Therefore: x=1 only

  7. Emily778
    • 2 years ago
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    is that all? jeez, thanks Lol

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