anonymous
  • anonymous
check for extraneous solutions. sqrt x+7-x=1 Please show step by step on how to do this. Thankyou.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Let \(u=\sqrt{x}\), then x = \(u^2\) Now, the equation becomes \[u+7-u^2=1\] Can you do it?
anonymous
  • anonymous
Wat?
anonymous
  • anonymous
@Krazete

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anonymous
  • anonymous
I don't get the way you're explaining it to me @RolyPoly
anonymous
  • anonymous
Please make use of parentheses. The way you write problems is sorta confusing. Is it √(x+7)-x=1 or ...?
anonymous
  • anonymous
I guess. Sorry, it doesn't show parentheses on my math problem.
anonymous
  • anonymous
Is the equation (1)\(\sqrt{ x+7-x} =1\) or (2) \(\sqrt{x}+7-x=1\)?
anonymous
  • anonymous
nvm, i got the answer. Thx
anonymous
  • anonymous
nvm.. I tried wolframalpha. But only get two step by steps each day:(
anonymous
  • anonymous
I'll have to get the answer tomorrow.
anonymous
  • anonymous
It would be better if you know how to solve it, instead of just relying on WolframAlpha.
anonymous
  • anonymous
eh, true. But lets be honest with ourselves, I'm never going to use this advanced of math in the future.
anonymous
  • anonymous
Honestly, I just need credits/passed classes
anonymous
  • anonymous
you can argue all you want, but it's true.
anonymous
  • anonymous
Don't want to argue, just want to help you pass the course and you can learn how to solve it at the same time :)
anonymous
  • anonymous
can you just show me please? I'm 18 lessons behind:(
nikato
  • nikato
\[\sqrt{x+7}-x=1\]
nikato
  • nikato
add x to both sides
anonymous
  • anonymous
It would be a different story if I wasn't that behind
anonymous
  • anonymous
\[\sqrt{x-7-x}=1\]\[\sqrt{x-7}-x=1\]\[\sqrt{x}-7-x=1\] Which one is your question?
anonymous
  • anonymous
like this @nikato |dw:1388896983931:dw|
anonymous
  • anonymous
the 2nd one @RolyPoly
nikato
  • nikato
yup
anonymous
  • anonymous
what next?
nikato
  • nikato
so now u have|dw:1388897108757:dw| now square both sides
anonymous
  • anonymous
i know 9 is the solution
anonymous
  • anonymous
what next?
nikato
  • nikato
did u square both sides. and simplified it?
anonymous
  • anonymous
how do I simplify it?
nikato
  • nikato
|dw:1388897450469:dw|does that make sense?
anonymous
  • anonymous
yeah.
anonymous
  • anonymous
what next?
nikato
  • nikato
subtract x and 7 on both sides so that the equation equal 0
nikato
  • nikato
|dw:1388897691356:dw|
anonymous
  • anonymous
what next? :D ha
nikato
  • nikato
|dw:1388897800670:dw| can u factor the right side?
anonymous
  • anonymous
can you show me? eheh
nikato
  • nikato
|dw:1388898386363:dw|
anonymous
  • anonymous
9?
anonymous
  • anonymous
@nikato
anonymous
  • anonymous
it has to be 9.
nikato
  • nikato
no, i dont think 9 is a solution. try pluggin it back into the origianl equation. it doesnt work
nikato
  • nikato
|dw:1388899069611:dw|
anonymous
  • anonymous
then you did it wrong. Ugh. Wolfram said it was 9
nikato
  • nikato
no, im for sure 9 is not an answer. it doesnt make sense. its one fo those^
anonymous
  • anonymous
@Krazete is he wrong or not?
anonymous
  • anonymous
sorry, nikato. I gotta make sure.
nikato
  • nikato
yea, its fine. whatever u feel is right
anonymous
  • anonymous
nikato's right.
anonymous
  • anonymous
okayy,, it's just wolfram said the solution was 9. But I guess it's better to have something than nothing at all.
nikato
  • nikato
maybe u typed in the wrong equation in wolfrma
anonymous
  • anonymous
Look at what Wolfram says under "input." Is it the same as your problem? It might've calculated √x instead of √(x+7). Parentheses are quite important.
anonymous
  • anonymous
nikato, what do I do next? Sorry for doubting you
nikato
  • nikato
|dw:1388899779946:dw| solve for x. did most of the work. should be easy for u. there are suppose to be 2 answers
anonymous
  • anonymous
one of them is 2.
nikato
  • nikato
yes. and the other?
anonymous
  • anonymous
o?
nikato
  • nikato
no, -3. so now u want to find if there is anyextraneous answers
nikato
  • nikato
plug both back into the equation and see if they make sense|dw:1388900195738:dw|
anonymous
  • anonymous
ugh. How much more is there??
anonymous
  • anonymous
what next?
nikato
  • nikato
no, this is it. check if both of those equation are true. if they are not, then that "x" is extraneous
anonymous
  • anonymous
it's 1.
anonymous
  • anonymous
thanks. :p
nikato
  • nikato
WAIT NO. its either 2 or -3. i helped plug in both in for x the first one is x=2 and the other is x=-3
anonymous
  • anonymous
I did it in my calculator. How'd you get your answer?
nikato
  • nikato
no, thats not what i meant
nikato
  • nikato
|dw:1388901004098:dw|
anonymous
  • anonymous
I'm sorry, I still don't get how you got those answers. I got -5 and 1. 1 was correct. -5 was incorrect.
nikato
  • nikato
yes. so that means -3 is the extraneous answer. remember how we worked the problem, and got 2 and -3 as the naswer. however when u plug -3 back into the original equation u get -5 instead of 1. which means the answer doesnt "work" which we call an extraneous answer
anonymous
  • anonymous
so what is the answer???
nikato
  • nikato
just 2
nikato
  • nikato
becuz like i said ^ -3 is an extraneous solution
anonymous
  • anonymous
so, I would put "x=2 only"?
nikato
  • nikato
yup

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