Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Emily778 Group Title

Solve. Check for extraneous solutions. sqrt(x+srt2x)=sqrt2x. Please show step by step instruction. Thankyou.

  • 11 months ago
  • 11 months ago

  • This Question is Closed
  1. oldrin.bataku Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    $$\sqrt{x+\sqrt{2x}}=\sqrt{2x}$$is that correct?

    • 11 months ago
  2. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah.

    • 11 months ago
  3. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @oldrin.bataku

    • 11 months ago
  4. oldrin.bataku Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, first thing we want to do is square both sides to get rid of the first radicals:$$\sqrt{x+\sqrt{2x}}=\sqrt{2x}\\\left(\sqrt{x+\sqrt{2x}}\right)^2=\left(\sqrt{2x}\right)^2\\x+\sqrt{2x}=2x\\\sqrt{2x}=2x-x\\\sqrt{2x}=x$$now we square again:$$\left(\sqrt{2x}\right)^2=x^2\\2x=x^2\\x^2-2x=0\\x(x-2)=0$$

    • 11 months ago
  5. oldrin.bataku Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    to verify these solutions are not extraneous, plug them back in.

    • 11 months ago
  6. Emily778 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    How? And thank you

    • 11 months ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.