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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\[4y^2+8y+7=4\]\[4y^2+8y+7\color{red} { 4 } =4\color{red} { 4 }\]\[4y^2+8y+3=0\]look for the a b c and plug them into the quadratic formula.\[\color{blue} { 4 }y^2+\color{blue} { 8 }y+\color{blue} { 3 }=0\]\[\color{green} { a=4 ~~~~~~~ }\color{green} { b=8 ~~~~~~~ }\color{green} { c=3 ~~~~~~~ }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\color{red}{ \frac{\huge\color{blue}{ 8 } ±\sqrt{\huge\color{blue}{ 8 } ^2(4 \times \huge\color{blue}{ 4 } \times \huge\color{blue}{ 7 } )}}{2 \times \huge\color{blue}{ 4} }}\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\color{goldenrod}{ \frac{8±\sqrt{48}}{8} }\]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0if you haven't learned about imaginary number (I am talking about "i") then simply say no solution. Now, if you have lets go on... \[\huge\color{goldenrod}{ \frac{8±4i \sqrt{3}}{8} }\] and divide top and bottom by 4, \[\huge\color{cornflowerblue}{ \frac{2±i \sqrt{3}}{2} }\]
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