anonymous
  • anonymous
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Mathematics
schrodinger
  • schrodinger
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ganeshie8
  • ganeshie8
you have two arcs of radius 10
ganeshie8
  • ganeshie8
each arc is measuring exactly 1/4th of circle (why ?)
ganeshie8
  • ganeshie8
so you can calculate the perimeter of shaded region ?

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anonymous
  • anonymous
so.. if i get the arc measures.. i'll just add both then i can already have the perimeter?
anonymous
  • anonymous
Do you know what is the perimeter of a full circle? If you do you can find the shaded one. As that is twice the quarter of a circle. Thus 2*1/4=1/2 The perimeter is half of the full circle. (with radius=10)
anonymous
  • anonymous
my answer is.. P=900, is it correct?
anonymous
  • anonymous
Seems wrong. \[\pi \] Is missing for sure.
anonymous
  • anonymous
What is the perimeter of a circle with radius=r?
anonymous
  • anonymous
15.71 ?
anonymous
  • anonymous
62.83
anonymous
  • anonymous
Do not try to jump steps. One at a time, otherwise you will make too many mistakes. So we will start with a circle of any radius=r. This circle has perimeter: \[P=2\pi r \] Is this clear?
anonymous
  • anonymous
yep, perimeter's 62.83 approximately
anonymous
  • anonymous
If r=10 as in this question. Now next step, first look at one arc of the graph. (half the perimeter asked) What fraction is this arc of the full circle?
anonymous
  • anonymous
1/4 of the circle
anonymous
  • anonymous
Correct, thus one arc has perimeter: \[\frac{ 1 }{ 4 } 2\pi r \]
anonymous
  • anonymous
We need two arcs, so need to multiply the above equation by 2. \[2*\frac{ 1 }{ 4 } 2\pi r =\pi r\]
anonymous
  • anonymous
\[solution: P=10\pi \]
anonymous
  • anonymous
15.71.. so.. 31.42 :)
anonymous
  • anonymous
did i get it right?
anonymous
  • anonymous
Yes but I am 100% confident that your maths teacher will not like the solution written as 31.42, as it is not precise. The solution is \[10 \pi \]
anonymous
  • anonymous
Hahah, yeah maybe. Alright. Got that. Thank you sooo much:)
Kainui
  • Kainui
@Andras Don't be so sure. Often times in courses like this the teacher prefers that you assume pi=3.14, which is probably exactly what his teacher expects since he's already doing it this way.
anonymous
  • anonymous
You might be right but that hurts my soul :(

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