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- anonymous

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- schrodinger

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- ganeshie8

you have two arcs of radius 10

- ganeshie8

each arc is measuring exactly 1/4th of circle (why ?)

- ganeshie8

so you can calculate the perimeter of shaded region ?

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## More answers

- anonymous

so.. if i get the arc measures.. i'll just add both then i can already have the perimeter?

- anonymous

Do you know what is the perimeter of a full circle?
If you do you can find the shaded one. As that is twice the quarter of a circle. Thus 2*1/4=1/2
The perimeter is half of the full circle. (with radius=10)

- anonymous

my answer is.. P=900, is it correct?

- anonymous

Seems wrong. \[\pi \]
Is missing for sure.

- anonymous

What is the perimeter of a circle with radius=r?

- anonymous

15.71 ?

- anonymous

62.83

- anonymous

Do not try to jump steps. One at a time, otherwise you will make too many mistakes.
So we will start with a circle of any radius=r.
This circle has perimeter:
\[P=2\pi r \]
Is this clear?

- anonymous

yep, perimeter's 62.83 approximately

- anonymous

If r=10 as in this question.
Now next step, first look at one arc of the graph. (half the perimeter asked)
What fraction is this arc of the full circle?

- anonymous

1/4 of the circle

- anonymous

Correct, thus one arc has perimeter:
\[\frac{ 1 }{ 4 } 2\pi r \]

- anonymous

We need two arcs, so need to multiply the above equation by 2.
\[2*\frac{ 1 }{ 4 } 2\pi r =\pi r\]

- anonymous

\[solution: P=10\pi \]

- anonymous

15.71..
so.. 31.42 :)

- anonymous

did i get it right?

- anonymous

Yes but I am 100% confident that your maths teacher will not like the solution written as 31.42, as it is not precise. The solution is \[10 \pi \]

- anonymous

Hahah, yeah maybe. Alright. Got that.
Thank you sooo much:)

- Kainui

@Andras Don't be so sure. Often times in courses like this the teacher prefers that you assume pi=3.14, which is probably exactly what his teacher expects since he's already doing it this way.

- anonymous

You might be right but that hurts my soul :(

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