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anonymous
 3 years ago

anonymous
 3 years ago


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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm quite confused. i dont know now T.T arc length: l = 2(theta)(r)(theta/360) l = 2(90)(5)(90/360) l=225 225x4 = 900 perimeter is 900cm

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2arc length : \(\large l = 2 (\theta)r \frac{\pi}{360}\) now try

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, wrong formula. ok let me solve it:)

lncognlto
 3 years ago
Best ResponseYou've already chosen the best response.1This is just a thought, but wouldn't the perimeter of the shaded region be equal to the circumference of a circle with a radius of 5 cm?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2Or, you can see that there are four quarter arcs of radius 5 which give u 1 complete perimeter of circle of radius 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my arc length is 7.85 so.. my perimeter of the shaded region is 31.42 approximately. is that right?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2\(\large \color{red}{\checkmark}\) next try if you get lncognlto's suggestion...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah, yes, thanks. and yup, what he said was right:) I just need a complete solution though:) thanks guys

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2both methods are considered complete solutions :) u wlc :) however ur teacher wud get more impressed if u do the lncognlto's method...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, haha, alright, will do that :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ganeshie8 , if this is the problem.. would the formula still be 2(theta)(r)(pi/360) or it should be 2(theta)(2)(pi/180)?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2Alright, here is the original formula : arc length \(l = r\theta\) \(\theta\) is in radians

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2to convert given \(\theta\) degrees into \(\theta\) radians, u multiply \(\frac{2\pi}{360}\) which is same as multiplying \(\frac{\pi}{180}\) : arc length \(l = r \theta \frac{2\pi}{360}\) \(\theta\) is in degrees now

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.2for the triangle, did they give u any dimensions ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much. yep, ill post my solution later for checking:)

lncognlto
 3 years ago
Best ResponseYou've already chosen the best response.1May I give another thought? xD

lncognlto
 3 years ago
Best ResponseYou've already chosen the best response.1If this triangle is equilateral, then the angles of each of the sectors is going to be 60 degrees. Thus three sectors together make 180 degrees, or half a circle. So the perimeter of the shaded region would then be equal to half the circumference of a circle with the radius equaling half the length of a side of the triangle.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, that's right. smart one. Hahaha. will remember that:)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.260 + 60 + 60 and 180 which one save u time ha ? I'm sure ur teacher wants u do this exactly as lcognlto suggests !
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