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arc length :
\(\large l = 2 (\theta)r \frac{\pi}{360}\)
now try

oh, wrong formula. ok let me solve it:)

^^ Yes :)

my arc length is 7.85
so.. my perimeter of the shaded region is 31.42 approximately. is that right?

\(\large \color{red}{\checkmark}\)
next try if you get lncognlto's suggestion...

oh, haha, alright, will do that :)

good :D

@ganeshie8 , if this is the problem..
would the formula still be 2(theta)(r)(pi/360)
or it should be 2(theta)(2)(pi/180)?

Alright, here is the original formula :-
arc length \(l = r\theta\)
\(\theta\) is in radians

for the triangle, did they give u any dimensions ?

thank you so much.
yep, ill post my solution later for checking:)

May I give another thought? xD

sure:)

sure :)

oh, that's right. smart one. Hahaha. will remember that:)

i believe so too:)