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stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
I'm quite confused. i dont know now T.T arc length: l = 2(theta)(r)(theta/360) l = 2(90)(5)(90/360) l=225 225x4 = 900 perimeter is 900cm
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
arc length : \(\large l = 2 (\theta)r \frac{\pi}{360}\) now try
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
oh, wrong formula. ok let me solve it:)
 8 months ago

lncognlto Group TitleBest ResponseYou've already chosen the best response.1
This is just a thought, but wouldn't the perimeter of the shaded region be equal to the circumference of a circle with a radius of 5 cm?
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
Or, you can see that there are four quarter arcs of radius 5 which give u 1 complete perimeter of circle of radius 5
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
^^ Yes :)
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
my arc length is 7.85 so.. my perimeter of the shaded region is 31.42 approximately. is that right?
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
\(\large \color{red}{\checkmark}\) next try if you get lncognlto's suggestion...
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
ah, yes, thanks. and yup, what he said was right:) I just need a complete solution though:) thanks guys
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
both methods are considered complete solutions :) u wlc :) however ur teacher wud get more impressed if u do the lncognlto's method...
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
oh, haha, alright, will do that :)
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
@ganeshie8 , if this is the problem.. would the formula still be 2(theta)(r)(pi/360) or it should be 2(theta)(2)(pi/180)?
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
Alright, here is the original formula : arc length \(l = r\theta\) \(\theta\) is in radians
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
to convert given \(\theta\) degrees into \(\theta\) radians, u multiply \(\frac{2\pi}{360}\) which is same as multiplying \(\frac{\pi}{180}\) : arc length \(l = r \theta \frac{2\pi}{360}\) \(\theta\) is in degrees now
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
for the triangle, did they give u any dimensions ?
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
thank you so much. yep, ill post my solution later for checking:)
 8 months ago

lncognlto Group TitleBest ResponseYou've already chosen the best response.1
May I give another thought? xD
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
sure:)
 8 months ago

lncognlto Group TitleBest ResponseYou've already chosen the best response.1
If this triangle is equilateral, then the angles of each of the sectors is going to be 60 degrees. Thus three sectors together make 180 degrees, or half a circle. So the perimeter of the shaded region would then be equal to half the circumference of a circle with the radius equaling half the length of a side of the triangle.
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
oh, that's right. smart one. Hahaha. will remember that:)
 8 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.2
60 + 60 + 60 and 180 which one save u time ha ? I'm sure ur teacher wants u do this exactly as lcognlto suggests !
 8 months ago

stupidinmath Group TitleBest ResponseYou've already chosen the best response.0
i believe so too:)
 8 months ago
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