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maaseyah11

  • one year ago

\l

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  1. suckerofmath
    • one year ago
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    Whats the third number on the price side?

  2. suckerofmath
    • one year ago
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    If they are 3$ each, all you have to do is find out how many time 3 will go into 18 and there's your answer.

  3. suckerofmath
    • one year ago
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    54?!?!?!?! Where did you get that?!?!?!

  4. suckerofmath
    • one year ago
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    Yes it's 6. Good Job.

  5. suckerofmath
    • one year ago
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    Sure. I'll try.

  6. suckerofmath
    • one year ago
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    Would you mind typing out the table? Please do it like 1,#

  7. suckerofmath
    • one year ago
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    Every time side (A) of the table goes up 1, side (B) of the table goes up one too. So all you have to do is take a piece of paper and start at the last number given and count up until your (A) collom reaches 22. Let me know if you need more help.

  8. suckerofmath
    • one year ago
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    Do you not have the chart pulled up in front of you?

  9. suckerofmath
    • one year ago
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    Add 1 to the A side and 1 to the B side.

  10. suckerofmath
    • one year ago
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    7 on the B side is 14. 8 B side is 15. Or are you trying 4 and 5 that's missing from your chart?

  11. suckerofmath
    • one year ago
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    If that is numbers that your trying to find, yes. Or are you trying to find 7 and 22 to finish the last two numbers on the chart too?

  12. suckerofmath
    • one year ago
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    I don't know what your assignment is but i'd assume it might be both...

  13. suckerofmath
    • one year ago
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    Ok then it's 7 and 22. Have you found out what they are?

  14. suckerofmath
    • one year ago
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    What do you mean by that?? Have you found that 7 and 22 are on the B side of the chart?

  15. suckerofmath
    • one year ago
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    On side A, The numbers on the given chart are 7 and 22. Would you like me to just tell you?

  16. suckerofmath
    • one year ago
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    A B 7 14 22 29

  17. suckerofmath
    • one year ago
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    You're welcome. You should try to figure it out on your own next time.

  18. suckerofmath
    • one year ago
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    Please close this question.

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