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 11 months ago
can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2
 11 months ago
can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2

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RaphaelFilgueiras
 11 months ago
Best ResponseYou've already chosen the best response.1dw:1389330360749:dw

Rea201
 11 months ago
Best ResponseYou've already chosen the best response.0ok so the answer is 1/x^2+1/2

Rea201
 11 months ago
Best ResponseYou've already chosen the best response.0Wow why didn't i know that . Duhh :) Thank you very much!!

RaphaelFilgueiras
 11 months ago
Best ResponseYou've already chosen the best response.1you are welcome
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