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can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2
 3 months ago
 3 months ago
can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2
 3 months ago
 3 months ago

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RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
dw:1389330360749:dw
 3 months ago

Rea201Best ResponseYou've already chosen the best response.0
ok so the answer is 1/x^2+1/2
 3 months ago

Rea201Best ResponseYou've already chosen the best response.0
Wow why didn't i know that . Duhh :) Thank you very much!!
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
you are welcome
 3 months ago
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