Rea201
can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2



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RaphaelFilgueiras
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dw:1389330360749:dw

Rea201
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ok so the answer is 1/x^2+1/2


Rea201
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Wow why didn't i know that . Duhh :) Thank you very much!!

RaphaelFilgueiras
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you are welcome