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Rea201

  • 2 years ago

can someone help solve this. Find F'(x) for F(x)= Int((1/t^2)dt) Upper value=x^2 Lower value=2

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  1. RaphaelFilgueiras
    • 2 years ago
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    |dw:1389330360749:dw|

  2. Rea201
    • 2 years ago
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    ok so the answer is -1/x^2+1/2

  3. RaphaelFilgueiras
    • 2 years ago
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    yep

  4. Rea201
    • 2 years ago
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    Wow why didn't i know that . Duhh :) Thank you very much!!

  5. RaphaelFilgueiras
    • 2 years ago
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    you are welcome

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