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did you take the derivative?

Yep I got f'(x) = 2 sin(x) cos (2x) + 5 /cos (2x)-3 )^2

it is so long im not sure its right

|dw:1389408369353:dw|

could you help me solve that I have no idea how

use sin²(x)+cos²(x)=1-> cos²(x)=1-sin²(x), and then you will have only sin x in your equations

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Z means k belong to the interger set,it's just a generical ans

x= 0 and 2 pi will be your solutions

and pi

is that my min and max solutions?

and it would be decreasing because its positive right?

min x= pi max are both x=0 and 2pi

ok got it

when sin(x)> 0 it will be decreasing x in]0,pi[
when sinx(x)<0 it will be increasing x in ]pi,2pi[

decreasing f'<0
increasing f'>0

thank you so much

you are welcome