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kaylala Group Title

topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)

  • 9 months ago
  • 9 months ago

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  1. kaylala Group Title
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    \[[(\sec C-1)\div(\sec C +1)]=[(1-\cos C)\div(1+\cos C)]\]

    • 9 months ago
  2. hartnn Group Title
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    just one identity, sec C = 1/cos C

    • 9 months ago
  3. hartnn Group Title
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    rest is just algebraic simplification

    • 9 months ago
  4. kaylala Group Title
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    you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn

    • 9 months ago
  5. hartnn Group Title
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    thats correct, take the left side (sec C -1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?

    • 9 months ago
  6. kaylala Group Title
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    i really don't get what you mean @hartnn

    • 9 months ago
  7. hartnn Group Title
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    to prove that identity , we need to prove that left side = right side. so we take left side, (sec C -1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C -1)/(1/cos C +1) does this make sense ?

    • 9 months ago
  8. dumbcow Group Title
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    @hartnn already showed you what to do...are you having trouble with simplifying the fractions?

    • 9 months ago
  9. kaylala Group Title
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    oh i see now did i do it right?

    • 9 months ago
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  10. kaylala Group Title
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    but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow

    • 9 months ago
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