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kaylala
 one year ago
topic: PROVING IDENTITIES
(SEE COMMENTS)
(trigonometry)
kaylala
 one year ago
topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)

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kaylala
 one year ago
Best ResponseYou've already chosen the best response.0\[[(\sec C1)\div(\sec C +1)]=[(1\cos C)\div(1+\cos C)]\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1just one identity, sec C = 1/cos C

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1rest is just algebraic simplification

kaylala
 one year ago
Best ResponseYou've already chosen the best response.0you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1thats correct, take the left side (sec C 1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?

kaylala
 one year ago
Best ResponseYou've already chosen the best response.0i really don't get what you mean @hartnn

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1to prove that identity , we need to prove that left side = right side. so we take left side, (sec C 1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C 1)/(1/cos C +1) does this make sense ?

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0@hartnn already showed you what to do...are you having trouble with simplifying the fractions?

kaylala
 one year ago
Best ResponseYou've already chosen the best response.0oh i see now did i do it right?

kaylala
 one year ago
Best ResponseYou've already chosen the best response.0but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow
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