kaylala
  • kaylala
topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

kaylala
  • kaylala
\[[(\sec C-1)\div(\sec C +1)]=[(1-\cos C)\div(1+\cos C)]\]
hartnn
  • hartnn
just one identity, sec C = 1/cos C
hartnn
  • hartnn
rest is just algebraic simplification

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

kaylala
  • kaylala
you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn
hartnn
  • hartnn
thats correct, take the left side (sec C -1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?
kaylala
  • kaylala
i really don't get what you mean @hartnn
hartnn
  • hartnn
to prove that identity , we need to prove that left side = right side. so we take left side, (sec C -1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C -1)/(1/cos C +1) does this make sense ?
dumbcow
  • dumbcow
@hartnn already showed you what to do...are you having trouble with simplifying the fractions?
kaylala
  • kaylala
oh i see now did i do it right?
1 Attachment
kaylala
  • kaylala
but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow

Looking for something else?

Not the answer you are looking for? Search for more explanations.