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kaylala

  • one year ago

topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)

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  1. kaylala
    • one year ago
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    \[[(\sec C-1)\div(\sec C +1)]=[(1-\cos C)\div(1+\cos C)]\]

  2. hartnn
    • one year ago
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    just one identity, sec C = 1/cos C

  3. hartnn
    • one year ago
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    rest is just algebraic simplification

  4. kaylala
    • one year ago
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    you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn

  5. hartnn
    • one year ago
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    thats correct, take the left side (sec C -1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?

  6. kaylala
    • one year ago
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    i really don't get what you mean @hartnn

  7. hartnn
    • one year ago
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    to prove that identity , we need to prove that left side = right side. so we take left side, (sec C -1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C -1)/(1/cos C +1) does this make sense ?

  8. dumbcow
    • one year ago
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    @hartnn already showed you what to do...are you having trouble with simplifying the fractions?

  9. kaylala
    • one year ago
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    oh i see now did i do it right?

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  10. kaylala
    • one year ago
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    but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow

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