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kaylala

  • 2 years ago

topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)

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  1. kaylala
    • 2 years ago
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    \[[(\sec C-1)\div(\sec C +1)]=[(1-\cos C)\div(1+\cos C)]\]

  2. hartnn
    • 2 years ago
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    just one identity, sec C = 1/cos C

  3. hartnn
    • 2 years ago
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    rest is just algebraic simplification

  4. kaylala
    • 2 years ago
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    you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn

  5. hartnn
    • 2 years ago
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    thats correct, take the left side (sec C -1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?

  6. kaylala
    • 2 years ago
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    i really don't get what you mean @hartnn

  7. hartnn
    • 2 years ago
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    to prove that identity , we need to prove that left side = right side. so we take left side, (sec C -1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C -1)/(1/cos C +1) does this make sense ?

  8. dumbcow
    • 2 years ago
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    @hartnn already showed you what to do...are you having trouble with simplifying the fractions?

  9. kaylala
    • 2 years ago
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    oh i see now did i do it right?

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  10. kaylala
    • 2 years ago
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    but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow

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