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kaylala

  • 11 months ago

topic: PROVING IDENTITIES (SEE COMMENTS) (trigonometry)

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  1. kaylala
    • 11 months ago
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    \[[(\sec C-1)\div(\sec C +1)]=[(1-\cos C)\div(1+\cos C)]\]

  2. hartnn
    • 11 months ago
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    just one identity, sec C = 1/cos C

  3. hartnn
    • 11 months ago
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    rest is just algebraic simplification

  4. kaylala
    • 11 months ago
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    you have to prove it.. like there'd be a solution or way it will turn out to be equal @hartnn

  5. hartnn
    • 11 months ago
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    thats correct, take the left side (sec C -1)/ (sec C+1) now since sec C = 1/cos C replace every sec C on left side by 1/cos C thats the first step what do u get ?

  6. kaylala
    • 11 months ago
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    i really don't get what you mean @hartnn

  7. hartnn
    • 11 months ago
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    to prove that identity , we need to prove that left side = right side. so we take left side, (sec C -1)/ (sec C+1) we can now use all the known identities here, the one which will be useful here will be sec C = 1/ cos C so, we get our first step as, (1/cos C -1)/(1/cos C +1) does this make sense ?

  8. dumbcow
    • 11 months ago
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    @hartnn already showed you what to do...are you having trouble with simplifying the fractions?

  9. kaylala
    • 11 months ago
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    oh i see now did i do it right?

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  10. kaylala
    • 11 months ago
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    but my BIG question is how do you do it? you know, how to start the process and know that this identity is the one that should be used... and not the others. any tip? @hartnn @dumbcow

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