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How to find nth term of the series,and therefore Sum of n terms?

Mathematics
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\[\Large S_n=\frac{1}{1.4} + \frac{1}{4.7} + \frac{1}{7.10}..n \]
n'th term 1/n(n+3)

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Other answers:

but that doesn't match for n=3?
|dw:1389456863526:dw| do this for every term
yeah, 1/n(n+3) will not work,
that "...n" implies thatere are total n terms ?
yep
3n-2 3n+1
1/ [ (3n-2)(3n+1)] this works ?
how did u think of that ? :|
works i guess
easy difference of 3 so multiple of 3 1..4...7..are all 1 less than multiple of 3
***two less than
did u get what to do for each term ? partial fraction kind of thingi
how do i find Sn now? partial fraction?i remember it kinda - 1/3((3n-2)-(3n+1))/(3n-2)(3n-3) ?
did u get what i did in the drawing ?
which drawing O_O
if yes, do it for 2nd term and tell me what u get
why did u do that?
1/4=3/4?
i'll correct it , wait
|dw:1389457539226:dw|
do the same thing for 2nd term, then 3rd term, and observe what happens, then you'll know why that was done
okay
did you get your sum ?

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