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Ash90

  • one year ago

simplify the expression (x^2-10x+25)^1/2

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  1. Ash90
    • one year ago
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    i have (x-5)^2=((x-5)^2)1/2=(x-5) then i do [5, infinity) but the answer is wrong

  2. goformit100
    • one year ago
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    Use multinomial theorem.

  3. hartnn
    • one year ago
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    simplified form is x-5

  4. hartnn
    • one year ago
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    u need domain ?

  5. Ash90
    • one year ago
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    i have x-5 and for my domain answer i put...

  6. Ash90
    • one year ago
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    |dw:1389459862624:dw|

  7. Ash90
    • one year ago
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    or should it be...

  8. hartnn
    • one year ago
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    why ?? why can x not be less than 5 ?

  9. Ash90
    • one year ago
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    |dw:1389459912753:dw|

  10. hartnn
    • one year ago
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    whats the domain of x-5 ?

  11. hartnn
    • one year ago
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    what if x= 3 is that allowed value ?

  12. hartnn
    • one year ago
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    note that x-5 does not place any restrictions on x

  13. ParthKohli
    • one year ago
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    The simplified form is |x - 5|.

  14. ParthKohli
    • one year ago
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    The domain of that should be all real numbers. x^2 - 10x + 25 is always positive, so you can input everything.

  15. Ash90
    • one year ago
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    so 5

  16. ParthKohli
    • one year ago
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    No, (-infty,infty)

  17. Ash90
    • one year ago
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    yes everything like -infinity to positive infinity

  18. ParthKohli
    • one year ago
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    Yup.

  19. Ash90
    • one year ago
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    oh see i had the left with a bracket so that was wrong

  20. Ash90
    • one year ago
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    thanks

  21. ParthKohli
    • one year ago
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    Do you need the range as well?

  22. Ash90
    • one year ago
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    after i had messed it up i just started guessing

  23. Ash90
    • one year ago
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    let me see..

  24. Ash90
    • one year ago
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    yeah i think so

  25. ParthKohli
    • one year ago
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    OK, so the simplification is |x - 5|. Do you know what the range of any absolute value function is?

  26. Ash90
    • one year ago
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    the range would be [5, positive ) right?

  27. hartnn
    • one year ago
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    nopes, the range of |x| is x>=0

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