anonymous
  • anonymous
simplify the expression (x^2-10x+25)^1/2
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
i have (x-5)^2=((x-5)^2)1/2=(x-5) then i do [5, infinity) but the answer is wrong
goformit100
  • goformit100
Use multinomial theorem.
hartnn
  • hartnn
simplified form is x-5

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hartnn
  • hartnn
u need domain ?
anonymous
  • anonymous
i have x-5 and for my domain answer i put...
anonymous
  • anonymous
|dw:1389459862624:dw|
anonymous
  • anonymous
or should it be...
hartnn
  • hartnn
why ?? why can x not be less than 5 ?
anonymous
  • anonymous
|dw:1389459912753:dw|
hartnn
  • hartnn
whats the domain of x-5 ?
hartnn
  • hartnn
what if x= 3 is that allowed value ?
hartnn
  • hartnn
note that x-5 does not place any restrictions on x
ParthKohli
  • ParthKohli
The simplified form is |x - 5|.
ParthKohli
  • ParthKohli
The domain of that should be all real numbers. x^2 - 10x + 25 is always positive, so you can input everything.
anonymous
  • anonymous
so 5
ParthKohli
  • ParthKohli
No, (-infty,infty)
anonymous
  • anonymous
yes everything like -infinity to positive infinity
ParthKohli
  • ParthKohli
Yup.
anonymous
  • anonymous
oh see i had the left with a bracket so that was wrong
anonymous
  • anonymous
thanks
ParthKohli
  • ParthKohli
Do you need the range as well?
anonymous
  • anonymous
after i had messed it up i just started guessing
anonymous
  • anonymous
let me see..
anonymous
  • anonymous
yeah i think so
ParthKohli
  • ParthKohli
OK, so the simplification is |x - 5|. Do you know what the range of any absolute value function is?
anonymous
  • anonymous
the range would be [5, positive ) right?
hartnn
  • hartnn
nopes, the range of |x| is x>=0

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