anonymous
  • anonymous
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^-2+z^-1l)=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
its find the value of 2^(l1+z+z^2+z^-2-z^-1l) sry i wrote it wrong
goformit100
  • goformit100
is it IIT question ?
anonymous
  • anonymous
yup

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More answers

anonymous
  • anonymous
you can use z+z^2+z^3+z^4=0 for z=fifth root of unity
goformit100
  • goformit100
Show your working.
hartnn
  • hartnn
so you know how to solve it already
anonymous
  • anonymous
|dw:1389460828114:dw| what next
anonymous
  • anonymous
the options are 4,2,1,none
hartnn
  • hartnn
simplify this 1+z+z^2+z^-2+z^-1
hartnn
  • hartnn
(????)/z^2
anonymous
  • anonymous
i did it by taking the denominator |dw:1389461042399:dw|
anonymous
  • anonymous
|dw:1389461100403:dw|
hartnn
  • hartnn
z+z^2+z^3+z^4=0 is incorrect
hartnn
  • hartnn
that gives one root as z=0
hartnn
  • hartnn
z^5 =1 z^5 -1^5 = 0
hartnn
  • hartnn
(z-1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0
hartnn
  • hartnn
so your entire numerator of the exponent goes to 0
hartnn
  • hartnn
did u follow ? if yes, i think, you'll get the answer now :)
anonymous
  • anonymous
no u didnt saw that i corrected the question its 1-z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4
hartnn
  • hartnn
oops
anonymous
  • anonymous
|dw:1389461448241:dw|
hartnn
  • hartnn
then i should say, there's typing error in the question OR the answer is NONE
anonymous
  • anonymous
yup i also thought so thanks for your time by the way
hartnn
  • hartnn
because z is complex, so will be 2^(-2/z) welcome ^_^

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