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rishabhjaiswal225499
 one year ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?
rishabhjaiswal225499
 one year ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?

This Question is Closed

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0its find the value of 2^(l1+z+z^2+z^2z^1l) sry i wrote it wrong

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0is it IIT question ?

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0you can use z+z^2+z^3+z^4=0 for z=fifth root of unity

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0Show your working.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so you know how to solve it already

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0dw:1389460828114:dw what next

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0the options are 4,2,1,none

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2simplify this 1+z+z^2+z^2+z^1

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0i did it by taking the denominator dw:1389461042399:dw

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0dw:1389461100403:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2z+z^2+z^3+z^4=0 is incorrect

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2that gives one root as z=0

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2(z1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2so your entire numerator of the exponent goes to 0

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2did u follow ? if yes, i think, you'll get the answer now :)

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0no u didnt saw that i corrected the question its 1z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0dw:1389461448241:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2then i should say, there's typing error in the question OR the answer is NONE

rishabhjaiswal225499
 one year ago
Best ResponseYou've already chosen the best response.0yup i also thought so thanks for your time by the way

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2because z is complex, so will be 2^(2/z) welcome ^_^
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