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rishabhjaiswal225499
 2 years ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?
rishabhjaiswal225499
 2 years ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?

This Question is Closed

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0its find the value of 2^(l1+z+z^2+z^2z^1l) sry i wrote it wrong

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0is it IIT question ?

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0you can use z+z^2+z^3+z^4=0 for z=fifth root of unity

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so you know how to solve it already

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389460828114:dw what next

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0the options are 4,2,1,none

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2simplify this 1+z+z^2+z^2+z^1

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0i did it by taking the denominator dw:1389461042399:dw

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389461100403:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2z+z^2+z^3+z^4=0 is incorrect

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2that gives one root as z=0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2(z1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so your entire numerator of the exponent goes to 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2did u follow ? if yes, i think, you'll get the answer now :)

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0no u didnt saw that i corrected the question its 1z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389461448241:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2then i should say, there's typing error in the question OR the answer is NONE

rishabhjaiswal225499
 2 years ago
Best ResponseYou've already chosen the best response.0yup i also thought so thanks for your time by the way

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2because z is complex, so will be 2^(2/z) welcome ^_^
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