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rishabhjaiswal225499 Group Title

if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^-2+z^-1l)=?

  • 8 months ago
  • 8 months ago

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  1. rishabhjaiswal225499 Group Title
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    its find the value of 2^(l1+z+z^2+z^-2-z^-1l) sry i wrote it wrong

    • 8 months ago
  2. goformit100 Group Title
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    is it IIT question ?

    • 8 months ago
  3. rishabhjaiswal225499 Group Title
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    yup

    • 8 months ago
  4. rishabhjaiswal225499 Group Title
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    you can use z+z^2+z^3+z^4=0 for z=fifth root of unity

    • 8 months ago
  5. goformit100 Group Title
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    Show your working.

    • 8 months ago
  6. hartnn Group Title
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    so you know how to solve it already

    • 8 months ago
  7. rishabhjaiswal225499 Group Title
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    |dw:1389460828114:dw| what next

    • 8 months ago
  8. rishabhjaiswal225499 Group Title
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    the options are 4,2,1,none

    • 8 months ago
  9. hartnn Group Title
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    simplify this 1+z+z^2+z^-2+z^-1

    • 8 months ago
  10. hartnn Group Title
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    (????)/z^2

    • 8 months ago
  11. rishabhjaiswal225499 Group Title
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    i did it by taking the denominator |dw:1389461042399:dw|

    • 8 months ago
  12. rishabhjaiswal225499 Group Title
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    |dw:1389461100403:dw|

    • 8 months ago
  13. hartnn Group Title
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    z+z^2+z^3+z^4=0 is incorrect

    • 8 months ago
  14. hartnn Group Title
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    that gives one root as z=0

    • 8 months ago
  15. hartnn Group Title
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    z^5 =1 z^5 -1^5 = 0

    • 8 months ago
  16. hartnn Group Title
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    (z-1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0

    • 8 months ago
  17. hartnn Group Title
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    so your entire numerator of the exponent goes to 0

    • 8 months ago
  18. hartnn Group Title
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    did u follow ? if yes, i think, you'll get the answer now :)

    • 8 months ago
  19. rishabhjaiswal225499 Group Title
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    no u didnt saw that i corrected the question its 1-z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4

    • 8 months ago
  20. hartnn Group Title
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    oops

    • 8 months ago
  21. rishabhjaiswal225499 Group Title
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    |dw:1389461448241:dw|

    • 8 months ago
  22. hartnn Group Title
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    then i should say, there's typing error in the question OR the answer is NONE

    • 8 months ago
  23. rishabhjaiswal225499 Group Title
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    yup i also thought so thanks for your time by the way

    • 8 months ago
  24. hartnn Group Title
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    because z is complex, so will be 2^(-2/z) welcome ^_^

    • 8 months ago
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