A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 2 years ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?
anonymous
 2 years ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?

This Question is Closed

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0its find the value of 2^(l1+z+z^2+z^2z^1l) sry i wrote it wrong

goformit100
 2 years ago
Best ResponseYou've already chosen the best response.0is it IIT question ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0you can use z+z^2+z^3+z^4=0 for z=fifth root of unity

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so you know how to solve it already

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389460828114:dw what next

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the options are 4,2,1,none

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2simplify this 1+z+z^2+z^2+z^1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i did it by taking the denominator dw:1389461042399:dw

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389461100403:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2z+z^2+z^3+z^4=0 is incorrect

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2that gives one root as z=0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2(z1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so your entire numerator of the exponent goes to 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2did u follow ? if yes, i think, you'll get the answer now :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0no u didnt saw that i corrected the question its 1z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389461448241:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2then i should say, there's typing error in the question OR the answer is NONE

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yup i also thought so thanks for your time by the way

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2because z is complex, so will be 2^(2/z) welcome ^_^
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.