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if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?
 3 months ago
 3 months ago
if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^2+z^1l)=?
 3 months ago
 3 months ago

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rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
its find the value of 2^(l1+z+z^2+z^2z^1l) sry i wrote it wrong
 3 months ago

goformit100Best ResponseYou've already chosen the best response.0
is it IIT question ?
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
you can use z+z^2+z^3+z^4=0 for z=fifth root of unity
 3 months ago

goformit100Best ResponseYou've already chosen the best response.0
Show your working.
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
so you know how to solve it already
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
dw:1389460828114:dw what next
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
the options are 4,2,1,none
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
simplify this 1+z+z^2+z^2+z^1
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
i did it by taking the denominator dw:1389461042399:dw
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
dw:1389461100403:dw
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
z+z^2+z^3+z^4=0 is incorrect
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
that gives one root as z=0
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
(z1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
so your entire numerator of the exponent goes to 0
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
did u follow ? if yes, i think, you'll get the answer now :)
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
no u didnt saw that i corrected the question its 1z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
dw:1389461448241:dw
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
then i should say, there's typing error in the question OR the answer is NONE
 3 months ago

rishabhjaiswal225499Best ResponseYou've already chosen the best response.0
yup i also thought so thanks for your time by the way
 3 months ago

hartnnBest ResponseYou've already chosen the best response.2
because z is complex, so will be 2^(2/z) welcome ^_^
 3 months ago
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