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if z is the non real fifth root of unity then the value of ^(l 1+z+z^2+z^-2+z^-1l)=?

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its find the value of 2^(l1+z+z^2+z^-2-z^-1l) sry i wrote it wrong
is it IIT question ?

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Other answers:

you can use z+z^2+z^3+z^4=0 for z=fifth root of unity
Show your working.
so you know how to solve it already
|dw:1389460828114:dw| what next
the options are 4,2,1,none
simplify this 1+z+z^2+z^-2+z^-1
i did it by taking the denominator |dw:1389461042399:dw|
z+z^2+z^3+z^4=0 is incorrect
that gives one root as z=0
z^5 =1 z^5 -1^5 = 0
(z-1)(1+z+z^2+z^3+z^4) = 0 as z not = 1 (1+z+z^2+z^3+z^4) = 0
so your entire numerator of the exponent goes to 0
did u follow ? if yes, i think, you'll get the answer now :)
no u didnt saw that i corrected the question its 1-z+z^2+z^3+z^4 and not 1+z+z^2+z^3+z^4
then i should say, there's typing error in the question OR the answer is NONE
yup i also thought so thanks for your time by the way
because z is complex, so will be 2^(-2/z) welcome ^_^

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