anonymous
  • anonymous
Is x= -1.75 the answer to this? I have already worked it out. I am just checking it. 4x+2(x+1)=9
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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hartnn
  • hartnn
6x +2 = 9 6x = 7 x= 7/6 x= 1.1667 how did u get -1.75 ?
anonymous
  • anonymous
first plug in your answer and if the answer matches up to 9 then thats your answer
anonymous
  • anonymous
4x+2(x+1)=9 4x+2-2(x+1)=9-2 4x(x+1)=7 4x=7 4x/4=7/4 x=1.75 Sorry I meant to put positive 1.75 not negative. But I still have a feeling that my answer is incorrect.

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anonymous
  • anonymous
well take 1.75 and plug it in for x and what do you get
anonymous
  • anonymous
not 9. so im incorrect
hartnn
  • hartnn
4x+2(x+1)=9 4x+2-2(x+1)=9-2 itself is incorrect. why did u subtract 2 ? and its not done properly
anonymous
  • anonymous
okay. so what is the first step to do? I have not had math in about a year so I need some refreshing. My teacher gave us practice problems for the first day, so she didn't teach or go over anything, so I am very lost.
hartnn
  • hartnn
4x+2(x+1)=9 1st step is to simplify 2(x+1) by distributing |dw:1389463858607:dw|
anonymous
  • anonymous
so 2x?
anonymous
  • anonymous
or 3x?
hartnn
  • hartnn
|dw:1389464033269:dw|
hartnn
  • hartnn
4x+2(x+1)=9 4x+2x+2=9 now subtract 2 from both sides.
anonymous
  • anonymous
so it was 2x? And I have to keep the +2?
hartnn
  • hartnn
4x+2x+2=9 4x+2x = 9-2 can u solve further ? 4x+2x = ???
anonymous
  • anonymous
x=7/6
hartnn
  • hartnn
yes, thats correct :)
anonymous
  • anonymous
Thank you so much! I just didn't remember the distributive property part.
hartnn
  • hartnn
you're welcome ^_^ keep practicing :)
anonymous
  • anonymous
I definitely will. :)
phi
  • phi
You check out Khan's videos to refresh your memory for example http://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-variables-expressions/cc-7th-manipulating-expressions/v/combining-like-terms-and-the-distributive-property In general, if you have a question, search his site for a pertinent video.
anonymous
  • anonymous
Okay, thank you. :)

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