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anonymous
 2 years ago
Use basic identities to simplify the expression. one divided by cotangent of theta to the second power. + sec θ cos θ
anonymous
 2 years ago
Use basic identities to simplify the expression. one divided by cotangent of theta to the second power. + sec θ cos θ

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0please help me! I am taking precalc online and don't understand a single thing about basic identities

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2so its \(\huge \dfrac{1}{\cot^2 \theta + \sec \theta \cos \theta} \)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2firstly, use the identity that sec theta = 1/cos theta so, sec theta cos theta = 1 and do you know what is \(\large 1+\cot^2 \theta = ... ?\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0only the cot^2theta is the denominator

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0no I don't know, I am COMPLETELY lost in this subject

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2okk., so anyways you can use sec theta cos theta = 1 \(\large \dfrac{1}{\cot^2 \theta }+1 \)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2now 1/ cot theta = tan theta so, \(\large \tan^2 \theta+1 \)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2and ther's a standard pythagorean identity that \(\large 1+\tan^2 \theta = \sec^2 \theta \) thats it! :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0can you walk me through another please?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Simplify the expression. quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity secant of x to the power of two plus cosecant of x to the power of two.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1389469428352:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2\(\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x }\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2ok, we use the identity that csc x = 1/ sin x sec x = 1/cos x

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2\(\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x } = \large \dfrac{\sin^2 x \cos^2 x }{\sin^2 x + \cos^2 x }\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2now we can use the famous pythagorean identity \(\Large \color{red}{\sin^2x + \cos^2 x =1 }\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2what remains is your answer! :)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so the answer is just 1? or am I wrong?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2denominator = 1 yes what remains is numerator sin^2 x cos^2 x

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2you have choices for this too ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yes I do the choices are: sin^2x cos^2x 1 1

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0im sorry im so stupid. im usually really good at math but precalc just makes no sense to me

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2oops, i did a simplification error \(\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x } = \large \dfrac{1 }{\sin^2 x + \cos^2 x } = 1\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0okay and i have a question. next year I planned on taking ap stat. is that anything like precalc because i hope not. is it easier or harder?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2if you practice less, math is hard. if you practice more, math is easy. irrespective of any topic/subject

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0well are the concepts of ap stat very similar to or very different to those of precalculus?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2statistics is a different branch of math altogether, so very different.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0i just think I'm not good at online class taking because I learn better from an actual person rather than a computer screen. I need the physical classroom environment and a teacher to give me instruction.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0what kind of problems does ap stat entail? word problems? graphs?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay thank you soooooo much! is there anything else that i should know?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2try to take up easy questions before going to harder ones. if you get stuck anytime, OpenStudy is always Open for you :)
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