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so its
\(\huge \dfrac{1}{\cot^2 \theta + \sec \theta \cos \theta} \)

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only the cot^2theta is the denominator

no I don't know, I am COMPLETELY lost in this subject

okk.,
so anyways you can use sec theta cos theta = 1
\(\large \dfrac{1}{\cot^2 \theta }+1 \)

now 1/ cot theta = tan theta
so,
\(\large \tan^2 \theta+1 \)

okay thank you!

can you walk me through another please?

sure

|dw:1389469428352:dw|

yes

\(\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x }\)

ok,
we use the identity that
csc x = 1/ sin x
sec x = 1/cos x

okay

now we can use the famous pythagorean identity
\(\Large \color{red}{\sin^2x + \cos^2 x =1 }\)

what remains is your answer! :)

so the answer is just 1? or am I wrong?

denominator = 1 yes
what remains is numerator
sin^2 x cos^2 x

you have choices for this too ?

yes I do the choices are:
sin^2x
cos^2x
-1
1

im sorry im so stupid. im usually really good at math but precalc just makes no sense to me

well are the concepts of ap stat very similar to or very different to those of pre-calculus?

statistics is a different branch of math altogether, so very different.

what kind of problems does ap stat entail? word problems? graphs?

both.

oh okay thank you soooooo much! is there anything else that i should know?

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