## help!!!!! Group Title Use basic identities to simplify the expression. one divided by cotangent of theta to the second power. + sec θ cos θ 6 months ago 6 months ago

1. help!!!!! Group Title

2. hartnn Group Title

so its $$\huge \dfrac{1}{\cot^2 \theta + \sec \theta \cos \theta}$$

3. hartnn Group Title

firstly, use the identity that sec theta = 1/cos theta so, sec theta cos theta = 1 and do you know what is $$\large 1+\cot^2 \theta = ... ?$$

4. help!!!!! Group Title

only the cot^2theta is the denominator

5. help!!!!! Group Title

no I don't know, I am COMPLETELY lost in this subject

6. hartnn Group Title

okk., so anyways you can use sec theta cos theta = 1 $$\large \dfrac{1}{\cot^2 \theta }+1$$

7. hartnn Group Title

now 1/ cot theta = tan theta so, $$\large \tan^2 \theta+1$$

8. hartnn Group Title

and ther's a standard pythagorean identity that $$\large 1+\tan^2 \theta = \sec^2 \theta$$ thats it! :)

9. help!!!!! Group Title

okay thank you!

10. help!!!!! Group Title

can you walk me through another please?

11. hartnn Group Title

sure

12. help!!!!! Group Title

Simplify the expression. quantity cosecant of x to the power of two times secant of x to the power of two divided by quantity secant of x to the power of two plus cosecant of x to the power of two.

13. help!!!!! Group Title

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14. help!!!!! Group Title

yes

15. hartnn Group Title

$$\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x }$$

16. hartnn Group Title

ok, we use the identity that csc x = 1/ sin x sec x = 1/cos x

17. help!!!!! Group Title

okay

18. hartnn Group Title

$$\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x } = \large \dfrac{\sin^2 x \cos^2 x }{\sin^2 x + \cos^2 x }$$

19. hartnn Group Title

now we can use the famous pythagorean identity $$\Large \color{red}{\sin^2x + \cos^2 x =1 }$$

20. hartnn Group Title

21. help!!!!! Group Title

so the answer is just 1? or am I wrong?

22. hartnn Group Title

denominator = 1 yes what remains is numerator sin^2 x cos^2 x

23. hartnn Group Title

you have choices for this too ?

24. help!!!!! Group Title

yes I do the choices are: sin^2x cos^2x -1 1

25. help!!!!! Group Title

im sorry im so stupid. im usually really good at math but precalc just makes no sense to me

26. hartnn Group Title

oops, i did a simplification error $$\large \dfrac{\csc^2 x \sec^2 x }{\sec^2 x + \csc^2 x } = \large \dfrac{1 }{\sin^2 x + \cos^2 x } = 1$$

27. help!!!!! Group Title

okay and i have a question. next year I planned on taking ap stat. is that anything like precalc because i hope not. is it easier or harder?

28. hartnn Group Title

if you practice less, math is hard. if you practice more, math is easy. irrespective of any topic/subject

29. help!!!!! Group Title

well are the concepts of ap stat very similar to or very different to those of pre-calculus?

30. hartnn Group Title

statistics is a different branch of math altogether, so very different.

31. help!!!!! Group Title

i just think I'm not good at online class taking because I learn better from an actual person rather than a computer screen. I need the physical classroom environment and a teacher to give me instruction.

32. help!!!!! Group Title

what kind of problems does ap stat entail? word problems? graphs?

33. hartnn Group Title

both.

34. help!!!!! Group Title

oh okay thank you soooooo much! is there anything else that i should know?

35. hartnn Group Title

try to take up easy questions before going to harder ones. if you get stuck anytime, OpenStudy is always Open for you :)