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stupidinmath
 one year ago

stupidinmath
 one year ago


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stupidinmath
 one year ago
Best ResponseYou've already chosen the best response.0A= big semicircle.. what's next?

MayankD
 one year ago
Best ResponseYou've already chosen the best response.1Just remove the semicircle on the left and place it in the gap on the right

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1this is SAT yes? I remember this one

Haleo
 one year ago
Best ResponseYou've already chosen the best response.0\[a= \pi*r ^{2}\] \[a= ( \pi * 10^{2} ) /2 = 157.079\]

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389510061781:dw

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389510085539:dw

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389510103621:dw so the area is equivalent to just the top semicircle... we merely moved the piece under the line to fill the hole to the right

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1the radius is very clearly \(r=10\) ergo the area is \(A=\pi r^2=\pi(10)^2=100\pi\)

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389510292746:dw

liliegirl
 one year ago
Best ResponseYou've already chosen the best response.0It is a semicircle so you need to divide by 2. The answer is 50pi + 25pi over 2. \[\frac{ 75\pi }{ 2 }\] is the answer.

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1oops  good catch. you do need to multiply by \(1/2\) to get just the top:$$\frac12\cdot100\pi=50\pi$$that being said, it is NOT \(\frac12(50\pi+25\pi)\)

liliegirl
 one year ago
Best ResponseYou've already chosen the best response.0dw:1389510798177:dw

stupidinmath
 one year ago
Best ResponseYou've already chosen the best response.0so.. also find that part and add it?

liliegirl
 one year ago
Best ResponseYou've already chosen the best response.0You need to add that because it is also shaded. The area of that part is 25pi over two.

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1@liliegirl that part is precisely the part we moved to fill in the top semicircle. it is now accounted for...

stupidinmath
 one year ago
Best ResponseYou've already chosen the best response.0so.. the answer is.. 314.16 right? thanks guys

liliegirl
 one year ago
Best ResponseYou've already chosen the best response.0@oldrin.bataku Ahhh, Sorry, I didn't notice.... :)))

oldrin.bataku
 one year ago
Best ResponseYou've already chosen the best response.1@stupidinmath no it's half of that, i.e. \(50\pi\)

stupidinmath
 one year ago
Best ResponseYou've already chosen the best response.0oh.. since its a semi circle.. k thanks :)
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