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stupidinmath

  • 11 months ago

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  1. Starr_DynastyT
    • 11 months ago
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    @shamil98

  2. stupidinmath
    • 11 months ago
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    A= big semicircle.. what's next?

  3. MayankD
    • 11 months ago
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    50pi

  4. MayankD
    • 11 months ago
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    Just remove the semicircle on the left and place it in the gap on the right

  5. oldrin.bataku
    • 11 months ago
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    this is SAT yes? I remember this one

  6. Haleo
    • 11 months ago
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    \[a= \pi*r ^{2}\] \[a= ( \pi * 10^{2} ) /2 = 157.079\]

  7. Haleo
    • 11 months ago
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    Isn't it right?

  8. oldrin.bataku
    • 11 months ago
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    |dw:1389510061781:dw|

  9. oldrin.bataku
    • 11 months ago
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    |dw:1389510085539:dw|

  10. oldrin.bataku
    • 11 months ago
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    |dw:1389510103621:dw| so the area is equivalent to just the top semicircle... we merely moved the piece under the line to fill the hole to the right

  11. oldrin.bataku
    • 11 months ago
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    the radius is very clearly \(r=10\) ergo the area is \(A=\pi r^2=\pi(10)^2=100\pi\)

  12. oldrin.bataku
    • 11 months ago
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    |dw:1389510292746:dw|

  13. liliegirl
    • 11 months ago
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    It is a semicircle so you need to divide by 2. The answer is 50pi + 25pi over 2. \[\frac{ 75\pi }{ 2 }\] is the answer.

  14. oldrin.bataku
    • 11 months ago
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    oops -- good catch. you do need to multiply by \(1/2\) to get just the top:$$\frac12\cdot100\pi=50\pi$$that being said, it is NOT \(\frac12(50\pi+25\pi)\)

  15. liliegirl
    • 11 months ago
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    |dw:1389510798177:dw|

  16. stupidinmath
    • 11 months ago
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    so.. also find that part and add it?

  17. liliegirl
    • 11 months ago
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    You need to add that because it is also shaded. The area of that part is 25pi over two.

  18. oldrin.bataku
    • 11 months ago
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    @liliegirl that part is precisely the part we moved to fill in the top semicircle. it is now accounted for...

  19. stupidinmath
    • 11 months ago
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    oh. right

  20. stupidinmath
    • 11 months ago
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    so.. the answer is.. 314.16 right? thanks guys

  21. liliegirl
    • 11 months ago
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    @oldrin.bataku Ahhh, Sorry, I didn't notice.... :)))

  22. oldrin.bataku
    • 11 months ago
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    @stupidinmath no it's half of that, i.e. \(50\pi\)

  23. stupidinmath
    • 11 months ago
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    oh.. since its a semi circle.. k thanks :)

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