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SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6post your question please.

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6( Loser66 is offline )

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1(1)/(sec x  tan x) = sec x + tan x

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6\[\huge\color{blue}{ \frac{1}{\sec(x)\tan(x)} =\sec(x)+\tan(x) } \]

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6\[\huge\color{blue}{ 1 =(\sec(x)+\tan(x) )(\sec(x)\tan(x))} \]

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6I multiplied both sides times sec(40)tan(40)

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1why? is that possible? i thought we can only manipulate 1 side?

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1shouldn't the other side be stable?

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Oh, then I take what I wrote back.

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6\[\huge\color{blue}{ \frac{1}{\sec(x)\tan(x)}=\sec(x)+\tan(x) } \] LEFT SIDE:\ top and bottom times sec(x)+tan(x) \[\huge\color{blue}{ \frac{\sec(x)\tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) } \] Now, use the identity for the bottom, \[\sec^2x=\tan^2x+1\]

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Oh, the top should say + not  sorry.

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6\[\huge\color{blue}{ \frac{\sec(x) \huge\color{red}{ + } \tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) } \]

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6HUGE HINT: \[\sec^2x=\tan^2x+1~~~~~~~ther efore~~~~~\sec^2x\tan^2x=1\]

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1i do not get it. sorry

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Do you get what I did before. the last huge post in blue with a red plus ?

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1nope but hey i found this: http://symbolab.com/solver/trigonometricidentitycalculator/prove%20%5Cfrac%7B1%7D%7B%5Csec(x)%5Ctan(x)%7D%3D%5Csec(x)%2B%5Ctan(x) but the answer doesnt seem to be equal is there a way you could make it equal???

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Don't try to look it up else where, follow me. lets start over, ok? \[\huge\color{green} { \frac{1}{\sec(x)\tan(x)}=\sec(x)+\tan(x) }\] I am working the left side: 1) Multiply top and bottom times sec(x)+tan(x)

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6\[\color{green} { \frac{\sec(x)+\tan(x)}{(~~\sec(x)\tan(x)~~)~(~~\sec(x)+\tan(x)~~)}=\sec(x)+\tan(x) }\] \[\color{green} { \frac{\sec(x)+\tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) }\] tell me if you don't get it.

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Now lets use an identity. \[\tan^2(x)+1=\sec^2(x)\] let's draw some conclusions. \[\tan^2(x)+1\color{blue} { \tan^2(x) } =\sec^2x\color{blue} { \tan^2(x) }\]\[1=\sec^2x\tan^2x\] look at the denominator, what is it now equal to? has your identity been verified?

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1yes. got it thanks @SolomonZelman

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6You welcome, no problem, just knowing identities that's all the skill involved.

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1and wow. that was shorter

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Yeah, I explained the same thing, but in a shorter way.

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1what's the technique?

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1how come you're so good at this?

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6what do you mean, the technique for what? Ohhh, I took trig last year, and got 97. I am just good at math and bad at other staff.

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1technique in answering / proving these trigonometric identities? you did it so fast and in a shorter and much efficient way that's really cool WOW! Congratz! good for you

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6Thank you! I am sure that if you try to do a lot of practice problems you will master them.

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1i really hope so. failing trigonometry is the last thing that i'd want

SolomonZelman
 11 months ago
Best ResponseYou've already chosen the best response.6WHAT?! FAILING?! what is your current grade may I ask ?

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.1last semester i got 2.0 in algebra now i'm taking trigonometry and it do is very hard. i dont have my grade yet since the 2nd semester just started.

kaylala
 11 months ago
Best ResponseYou've already chosen the best response.11 being the highest 3  pass 5  fail
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