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kaylala
Group Title
topic: PROVING IDENTITIES  help me please (SEE COMMENTS)
(trigonometry)
 10 months ago
 10 months ago
kaylala Group Title
topic: PROVING IDENTITIES  help me please (SEE COMMENTS) (trigonometry)
 10 months ago
 10 months ago

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kaylala Group TitleBest ResponseYou've already chosen the best response.1
@Loser66 help
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
post your question please.
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
( Loser66 is offline )
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
(1)/(sec x  tan x) = sec x + tan x
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
i noticed
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
\[\huge\color{blue}{ \frac{1}{\sec(x)\tan(x)} =\sec(x)+\tan(x) } \]
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
\[\huge\color{blue}{ 1 =(\sec(x)+\tan(x) )(\sec(x)\tan(x))} \]
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
I multiplied both sides times sec(40)tan(40)
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
why? is that possible? i thought we can only manipulate 1 side?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
shouldn't the other side be stable?
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Oh, then I take what I wrote back.
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
\[\huge\color{blue}{ \frac{1}{\sec(x)\tan(x)}=\sec(x)+\tan(x) } \] LEFT SIDE:\ top and bottom times sec(x)+tan(x) \[\huge\color{blue}{ \frac{\sec(x)\tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) } \] Now, use the identity for the bottom, \[\sec^2x=\tan^2x+1\]
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Oh, the top should say + not  sorry.
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
\[\huge\color{blue}{ \frac{\sec(x) \huge\color{red}{ + } \tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) } \]
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
HUGE HINT: \[\sec^2x=\tan^2x+1~~~~~~~ther efore~~~~~\sec^2x\tan^2x=1\]
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
i do not get it. sorry
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Do you get what I did before. the last huge post in blue with a red plus ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
nope but hey i found this: http://symbolab.com/solver/trigonometricidentitycalculator/prove%20%5Cfrac%7B1%7D%7B%5Csec(x)%5Ctan(x)%7D%3D%5Csec(x)%2B%5Ctan(x) but the answer doesnt seem to be equal is there a way you could make it equal???
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Don't try to look it up else where, follow me. lets start over, ok? \[\huge\color{green} { \frac{1}{\sec(x)\tan(x)}=\sec(x)+\tan(x) }\] I am working the left side: 1) Multiply top and bottom times sec(x)+tan(x)
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
\[\color{green} { \frac{\sec(x)+\tan(x)}{(~~\sec(x)\tan(x)~~)~(~~\sec(x)+\tan(x)~~)}=\sec(x)+\tan(x) }\] \[\color{green} { \frac{\sec(x)+\tan(x)}{\sec^2(x)\tan^2(x)}=\sec(x)+\tan(x) }\] tell me if you don't get it.
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Now lets use an identity. \[\tan^2(x)+1=\sec^2(x)\] let's draw some conclusions. \[\tan^2(x)+1\color{blue} { \tan^2(x) } =\sec^2x\color{blue} { \tan^2(x) }\]\[1=\sec^2x\tan^2x\] look at the denominator, what is it now equal to? has your identity been verified?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
yes. got it thanks @SolomonZelman
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
You welcome, no problem, just knowing identities that's all the skill involved.
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
and wow. that was shorter
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Yeah, I explained the same thing, but in a shorter way.
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
what's the technique?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
how come you're so good at this?
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
what do you mean, the technique for what? Ohhh, I took trig last year, and got 97. I am just good at math and bad at other staff.
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
technique in answering / proving these trigonometric identities? you did it so fast and in a shorter and much efficient way that's really cool WOW! Congratz! good for you
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
Thank you! I am sure that if you try to do a lot of practice problems you will master them.
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
i really hope so. failing trigonometry is the last thing that i'd want
 10 months ago

SolomonZelman Group TitleBest ResponseYou've already chosen the best response.6
WHAT?! FAILING?! what is your current grade may I ask ?
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
last semester i got 2.0 in algebra now i'm taking trigonometry and it do is very hard. i dont have my grade yet since the 2nd semester just started.
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
1 being the highest 3  pass 5  fail
 10 months ago

kaylala Group TitleBest ResponseYou've already chosen the best response.1
@SolomonZelman ^
 10 months ago
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