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Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry.
Its solving a quadratic equation that had complex numbers
 3 months ago
 3 months ago
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry. Its solving a quadratic equation that had complex numbers
 3 months ago
 3 months ago

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DragonFlameBest ResponseYou've already chosen the best response.0
:/ Sorry... I can't help..
 3 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
tried using the quadratic formula yet?
 3 months ago

0213Best ResponseYou've already chosen the best response.1
I tried it, i solved it but i got the wrong answers. I tried it over and over again. I looked up videos, still wrong answer
 3 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
\(\large \begin{array}{llll} {\color{red}{ 2}}x^2&{\color{blue}{ i}}x&{\color{green}{ 2+i}}=0\\ \uparrow &\ \uparrow &\quad \uparrow \\ {\color{red}{ a}}&\ {\color{blue}{ b}}&\quad {\color{green}{ c}} \end{array}\\ \quad \\ \bf x=\cfrac{i\pm\sqrt{i^24(2)(2+i)}}{2(2)}\implies x=\cfrac{i\pm\sqrt{18(2+i)}}{2(2)}\\ \quad \\ x=\cfrac{i\pm\sqrt{1+168i}}{2(2)}\implies x=\cfrac{i\pm\sqrt{158i}}{4}\)
 3 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
well.. that's.... as far as I can see it going... what does your answer say?
 3 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
hmmm I don't see it simplifying ... to that
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
dw:1389574709566:dw
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Ruffini's_rule
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
that is an algorithm
 3 months ago

0213Best ResponseYou've already chosen the best response.1
please explain...never learned that
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
dw:1389575164382:dw
 3 months ago

0213Best ResponseYou've already chosen the best response.1
wait...is this like synthetic division
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
dw:1389575421091:dw
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
this is the briotruffini algorithmm, i don't what is synthetic division
 3 months ago

0213Best ResponseYou've already chosen the best response.1
so in my question the root is 2?
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
no the root is one, the first coef in your polynomial is 2
 3 months ago

0213Best ResponseYou've already chosen the best response.1
how do i know what the root is?
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
one, was a easy root to see in that problem
 3 months ago

0213Best ResponseYou've already chosen the best response.1
oh. so if it had all 4...then it will be 2?
 3 months ago

0213Best ResponseYou've already chosen the best response.1
could u do it step by step and explain what you were doing at each step
 3 months ago

RaphaelFilgueirasBest ResponseYou've already chosen the best response.1
dw:1389575930097:dw
 3 months ago