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 one year ago
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry.
Its solving a quadratic equation that had complex numbers
 one year ago
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry. Its solving a quadratic equation that had complex numbers

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DragonFlame
 one year ago
Best ResponseYou've already chosen the best response.0:/ Sorry... I can't help..

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0tried using the quadratic formula yet?

0213
 one year ago
Best ResponseYou've already chosen the best response.1I tried it, i solved it but i got the wrong answers. I tried it over and over again. I looked up videos, still wrong answer

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \begin{array}{llll} {\color{red}{ 2}}x^2&{\color{blue}{ i}}x&{\color{green}{ 2+i}}=0\\ \uparrow &\ \uparrow &\quad \uparrow \\ {\color{red}{ a}}&\ {\color{blue}{ b}}&\quad {\color{green}{ c}} \end{array}\\ \quad \\ \bf x=\cfrac{i\pm\sqrt{i^24(2)(2+i)}}{2(2)}\implies x=\cfrac{i\pm\sqrt{18(2+i)}}{2(2)}\\ \quad \\ x=\cfrac{i\pm\sqrt{1+168i}}{2(2)}\implies x=\cfrac{i\pm\sqrt{158i}}{4}\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well.. that's.... as far as I can see it going... what does your answer say?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0hmmm I don't see it simplifying ... to that

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389574709566:dw

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1that is an algorithm

0213
 one year ago
Best ResponseYou've already chosen the best response.1please explain...never learned that

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389575164382:dw

0213
 one year ago
Best ResponseYou've already chosen the best response.1wait...is this like synthetic division

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389575421091:dw

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1this is the briotruffini algorithmm, i don't what is synthetic division

0213
 one year ago
Best ResponseYou've already chosen the best response.1so in my question the root is 2?

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1no the root is one, the first coef in your polynomial is 2

0213
 one year ago
Best ResponseYou've already chosen the best response.1how do i know what the root is?

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1one, was a easy root to see in that problem

0213
 one year ago
Best ResponseYou've already chosen the best response.1oh. so if it had all 4...then it will be 2?

0213
 one year ago
Best ResponseYou've already chosen the best response.1could u do it step by step and explain what you were doing at each step

RaphaelFilgueiras
 one year ago
Best ResponseYou've already chosen the best response.1dw:1389575930097:dw