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0213
 2 years ago
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry.
Its solving a quadratic equation that had complex numbers
0213
 2 years ago
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry. Its solving a quadratic equation that had complex numbers

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DragonFlame
 2 years ago
Best ResponseYou've already chosen the best response.0:/ Sorry... I can't help..

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0tried using the quadratic formula yet?

0213
 2 years ago
Best ResponseYou've already chosen the best response.1I tried it, i solved it but i got the wrong answers. I tried it over and over again. I looked up videos, still wrong answer

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0\(\large \begin{array}{llll} {\color{red}{ 2}}x^2&{\color{blue}{ i}}x&{\color{green}{ 2+i}}=0\\ \uparrow &\ \uparrow &\quad \uparrow \\ {\color{red}{ a}}&\ {\color{blue}{ b}}&\quad {\color{green}{ c}} \end{array}\\ \quad \\ \bf x=\cfrac{i\pm\sqrt{i^24(2)(2+i)}}{2(2)}\implies x=\cfrac{i\pm\sqrt{18(2+i)}}{2(2)}\\ \quad \\ x=\cfrac{i\pm\sqrt{1+168i}}{2(2)}\implies x=\cfrac{i\pm\sqrt{158i}}{4}\)

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0well.. that's.... as far as I can see it going... what does your answer say?

jdoe0001
 2 years ago
Best ResponseYou've already chosen the best response.0hmmm I don't see it simplifying ... to that

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1389574709566:dw

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1that is an algorithm

0213
 2 years ago
Best ResponseYou've already chosen the best response.1please explain...never learned that

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1389575164382:dw

0213
 2 years ago
Best ResponseYou've already chosen the best response.1wait...is this like synthetic division

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1389575421091:dw

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1this is the briotruffini algorithmm, i don't what is synthetic division

0213
 2 years ago
Best ResponseYou've already chosen the best response.1so in my question the root is 2?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1no the root is one, the first coef in your polynomial is 2

0213
 2 years ago
Best ResponseYou've already chosen the best response.1how do i know what the root is?

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1one, was a easy root to see in that problem

0213
 2 years ago
Best ResponseYou've already chosen the best response.1oh. so if it had all 4...then it will be 2?

0213
 2 years ago
Best ResponseYou've already chosen the best response.1could u do it step by step and explain what you were doing at each step

RaphaelFilgueiras
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1389575930097:dw