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0213
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Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry.
Its solving a quadratic equation that had complex numbers
 10 months ago
 10 months ago
0213 Group Title
Could someone walk me through this question and explain to me what happens. I have been working on it for 7 hours. I don't understand my prof and I might fail the class and I want to cry. Its solving a quadratic equation that had complex numbers
 10 months ago
 10 months ago

This Question is Closed

0213 Group TitleBest ResponseYou've already chosen the best response.1
\[2x^2ix2+i=0\]
 10 months ago

DragonFlame Group TitleBest ResponseYou've already chosen the best response.0
:/ Sorry... I can't help..
 10 months ago

DragonFlame Group TitleBest ResponseYou've already chosen the best response.0
@jdoe0001
 10 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
tried using the quadratic formula yet?
 10 months ago

DragonFlame Group TitleBest ResponseYou've already chosen the best response.0
Phew! GO JDOE!
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
I tried it, i solved it but i got the wrong answers. I tried it over and over again. I looked up videos, still wrong answer
 10 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
\(\large \begin{array}{llll} {\color{red}{ 2}}x^2&{\color{blue}{ i}}x&{\color{green}{ 2+i}}=0\\ \uparrow &\ \uparrow &\quad \uparrow \\ {\color{red}{ a}}&\ {\color{blue}{ b}}&\quad {\color{green}{ c}} \end{array}\\ \quad \\ \bf x=\cfrac{i\pm\sqrt{i^24(2)(2+i)}}{2(2)}\implies x=\cfrac{i\pm\sqrt{18(2+i)}}{2(2)}\\ \quad \\ x=\cfrac{i\pm\sqrt{1+168i}}{2(2)}\implies x=\cfrac{i\pm\sqrt{158i}}{4}\)
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
ok..got that
 10 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
well.. that's.... as far as I can see it going... what does your answer say?
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
x=1 and x=1+0.5i
 10 months ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
hmmm I don't see it simplifying ... to that
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
dw:1389574709566:dw
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Ruffini's_rule
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
how did u do that
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
that is an algorithm
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
please explain...never learned that
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
dw:1389575164382:dw
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
wait...is this like synthetic division
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
dw:1389575421091:dw
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
this is the briotruffini algorithmm, i don't what is synthetic division
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
so in my question the root is 2?
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
no the root is one, the first coef in your polynomial is 2
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
how do i know what the root is?
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
one, was a easy root to see in that problem
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
oh. so if it had all 4...then it will be 2?
 10 months ago

0213 Group TitleBest ResponseYou've already chosen the best response.1
could u do it step by step and explain what you were doing at each step
 10 months ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
dw:1389575930097:dw
 10 months ago