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anonymous
 2 years ago
What is the equation for the graph shown?
anonymous
 2 years ago
What is the equation for the graph shown?

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Definitely something involving tan(x)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Awesome, thank you! Any idea how to find the equation?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0For example the period of sin(x) is 2pi. (one complete oscilation)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0How do I find the equation simply by looking at a graph though?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0compare it to the base graph tan(x)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Wow I'm confused haha

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I'm still really confused as to how to find the equation of the graph though

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Is there a method to it?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0The equation should be \[\tan \left( \frac{ x\pi }{ 2 } \right)\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ok first off: Based on the shape of the graph, what trig function is this?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0@azetina you're right. not exactly sure how to explain this though.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0the second is \[\tan (x \pi)\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Like I said, compare the phase shift with the base graph tan x

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0and look at the zeros of the function

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Oh I get it that makes sense!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you so so much :)
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