A community for students.
Here's the question you clicked on:
 0 viewing
Singlemom76
 2 years ago
Hey everyone back to school can someone help with this problem (x+2)^1/2 (2x+4)+(x+2)^3/2
Singlemom76
 2 years ago
Hey everyone back to school can someone help with this problem (x+2)^1/2 (2x+4)+(x+2)^3/2

This Question is Closed

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0Are you supposed to simplify the problem?

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0ok look at the parentheses on the left. Can you pull out any common factors?

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0oh oops I mean one in the middle.

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0ok but what do I do with those darn exponents. LOL

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0just a sec, I'm working it out. will explain as soon as I'm done.

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0ok here goes: Pulling out the common 2, you get: 2(x+2)(x+2)^1/2 + (x+2)^3/2 right?

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0So now can you see any terms that can be pulled out of the addition?

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0actually first: can you simplify the left side of the addition at all?

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0the (x+2)^1/2 goes to the bottom and the 2 can be factored from the (2x+4) leaving 2(x+2) over (x+2)^1/2

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0notice that both have a base of (x+2). What does that mean about the exponents?

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0yea I'm sorry not a clue. Ugh Christmas break ruined me

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0When the bases are equal, 2 multiplied exponents can be added. for example: 2^2 * 2^3 = 2^5. In this case, the base is (x+2) and the exponents are 1 and 1/2. soo.....

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0I am so sorry and feel like an idiot right now. I get that the exponents are multiplied

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0exponents should be added. In this case 11/2 = 1/2. As a result: you get 2(x+2)^1/2 + (x+2)^3/2 right?

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0ok oops thats what I meant. But didn't the () exponent go to the denominator

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0you can do that too, but in this case it's simply easier to add up the exponents, eliminating the denominator altogether.

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0ok then what do I do?

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0Now you have a common term of (x+2)^1/2 that you can pull out of both terms in the addition. It's like the opposite of the distributive property.

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0Doing that, you get (x+2)^1/2 times(2 + x + 2), which simplifies to (x+4)(x+2)^1/2. and you're done.

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0so my final answer should be (x+2)^1/2 + (x+4)

alffer1
 2 years ago
Best ResponseYou've already chosen the best response.0oh wait no. They're multiplied, not added.

Singlemom76
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks (feel like an idiot) lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.